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Katen [24]
3 years ago
5

Which of the following equations would not be a line when graphed? Explain how you can tell by just looking at the equations.

Mathematics
2 answers:
klemol [59]3 years ago
8 0

Answer:

y=\frac{2}{x}

y= 6x^{2} -7

Step-by-step explanation:

A linear function is one that has the following form:

y= mx +b

Where m corresponds to the slope (degree of inclination of the line), and b the cut point on the y-axis.

Now we search among the options those that correspond to the linear function formula  

a.

y= 3x+4

Is a linear function where

m=3\\ b=4

b.

y=\frac{2}{x}

Is not a linear function equation since the variable x is in the denominator

c.

y=-5x  

Is a linear function where

m=-5\\ b=0

d.

y= 6x^{2} -7

Is not a linear function since the variable x is squared.

zlopas [31]3 years ago
5 0
Y=2/x. this equation has degree -1 whereas linear functions have degree 1

y=6x²-7 is nonlinear as it is degree 2
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Cual es el resultado de truncar a milésimos (3 decimales) 2/7 cuando lo convertimos a número decimal
Whitepunk [10]

The value of 2/7 expressed as a truncated decimal to the nearest thousandth is 0.286

Rational numbers are numbers written as the ratio of two integers. For example, the fraction 2/7 given is a rational number.

Expressing 2/7 as a decimal number will give;

2/7 = 0.2857142... (It gave repeated decimal values)

Truncating the repeating decimal to the nearest thousandth means writing the decimal to 3 decimal places

0.2857142 = 0.286 (to the nearest thousandth)

Hence the value of 2/7 expressed as a truncated decimal to the nearest thousandth is 0.286

Learn more here: brainly.com/question/24643812

4 0
3 years ago
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4 0
3 years ago
Can square root of 27 be simplified
Studentka2010 [4]
<span>Yes, square root of 27 can be simplified
</span>
\sqrt{27}= \sqrt{9*3}=3 \sqrt{3}


8 0
4 years ago
Read 2 more answers
Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c
nadya68 [22]

Answer:

A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] message SHOW_ME_THE_MONEY_  

Step-by-step explanation:

The matrix

A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message    Decoded message    message in letters by association

11 52        19 8    S H

-8 -9         15 23  O W

-13 -39        0 13   _ M

5 20         5 0   E _

12 56        20 8    T H

5 20         5 0    E _

-2 7           13 15  M O

9 41         14 5   N E

25 100       25 0    Y _

Then the message decoded is SHOW_ME_THE_MONEY_                                

3 0
3 years ago
Let f(x)= 7-2x Find a. f(4) b. f(h) c. f(4) + f(h) d. f(3+h)
anyanavicka [17]

Step-by-step explanation:

a) f(4) = 7-2(4)

= -1

b) f(h) = 7-2(h)

= 7-2h

c) f(4) + f(h) = -1 +(7-2h)

= 6-2h

h = 3

d) f(3+h) = 7-2(3+h)

= 7-6-2h

= -1-2h

2h= -1

h = -1/2

p/s = if the real answer is different with my answer, tell me also please. Im just a student that still learning.

4 0
3 years ago
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