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solong [7]
3 years ago
8

18 subtracted from a number is 35

Mathematics
2 answers:
kogti [31]3 years ago
3 0
X - 18 = 35. 53 is x, since 53 - 18 = 35.
disa [49]3 years ago
3 0

Answer:

53

Step-by-step explanation:

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This can be solved by using the normal approximation to the binomial distribution.
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The standard deviation is given by:
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z=\frac{5100-5000}{50}=2
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A century year such as 1900, 2000, or 2100 is a leap year only if it is a multiple of 400
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Food and clothing are shipped to victims of a natural disaster. Each carton of food will feed 13 ​people, while each carton of c
lutik1710 [3]

Answer:

  233 cartons of food; 467 cartons of clothing

Step-by-step explanation:

This linear programming problem can be formulated as two inequalities (in addition to the usual constraints that the variables be non-negative). One of these expresses the constraint on weight. Let f and c represent numbers of food and clothing containers, respectively.

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The other expresses the limit on volume.

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_____

<u>Feasible Region vertex</u>

We can subtract the boundary line equation of the first inequality from that of 5 times the second to find f:

  5(20f +5c) -(40f +25c) = 5(7000) -21000

  60f = 14000

  f = 233 1/3

The second boundary line equation can be rearranged to find c:

  c = 1400 -4f = 466 2/3

The nearest integer numbers to these values are ...

  (f, c) = (233, 467)

The other vertices of the feasible region are associated with one or the other variable being zero: (f, c) = (0, 840) or (350, 0).

<u>Check of Integer Solution</u>

Trying these in the constraint inequalities gives ...

  • 40·233 +25·467 = 20,995 < 21000
  • 20·233 +5·467 = 6995 < 7000

<u>Selection of the Answer</u>

The answer to the question will be the feasible region vertex that maximizes the number of people helped. That is, we want to maximize ...

  p = 13f + 6c

The values of p at the vertices are ...

  p = 13·233 + 6·467 = 5831

  p = 13·0 + 6·840 = 5040

  p = 13·350 + 6·0 = 2100

The most people are helped when the plane is filled with 233 food cartons and 467 clothing cartons.

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