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solong [7]
3 years ago
8

18 subtracted from a number is 35

Mathematics
2 answers:
kogti [31]3 years ago
3 0
X - 18 = 35. 53 is x, since 53 - 18 = 35.
disa [49]3 years ago
3 0

Answer:

53

Step-by-step explanation:

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Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
Someone pls help me with this I will make you brain
suter [353]

Answer:

Its A

Step-by-step explanation:

6 0
3 years ago
Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
Musya8 [376]

Formula for the perimeter of a quarter circle: C = ((pi x 2r) / 4) + 2r

C = ((3.14 + 12) / 4) + 12

C = 3.785 + 12

C = 15.79 meters

Hope this helps! :)

4 0
3 years ago
The cross section of a parabolic sound reflector at the Olympics has a diameter of 20 inches and is 25 inches deep. Write an equ
Arturiano [62]

Answer: 69

Step-by-step explanation: Sorry I do not know the answer because I am not smart.  I just need the points so I can answer more questions.  Have a great day though and I wish you luck with your question:)

7 0
3 years ago
Please help!!!!!!!!!!!!!!!!!!!!!!!!!!
Triss [41]

Answer:

The Blue box is your answer

Step-by-step explanation:

Multiply 4, 8, and 7 and you get 224. The problem states that it should not be over 250, and 224 is not over 250. So the blue box is your best go.

5 0
3 years ago
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