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prisoha [69]
3 years ago
10

( (6+4) (6+4) ) - (25 x 2)

Mathematics
1 answer:
Setler79 [48]3 years ago
4 0
50 because if you do PEMDAS you would do 6+4=10 and then again 6+4=10 you would have 10 and 10 in 2 different parenthesis so then go to 25*2=50 then multiply 10 and 10 which is 100 then subtract 50 from 100 which is 50 and then there is your answer
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Factor the expression.<br><br> 15n−18
Taya2010 [7]
Divide each term by 3...
15n - 8 = 3(5n - 6)


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What is 1 1/2 minus 1/4
vfiekz [6]
1 1/2 - 1/4
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That makes it 1 2/4 - 1/4. That equals 1 3/4.


Hope that this helped! :)
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Can somebody help me please first person to asnwer gets brainliest
garri49 [273]

Answer:

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Step-by-step explanation:

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2 years ago
The average daily volume of a computer stock in 2011 was ų=35.1 million shares, according to a reliable source. A stock analyst
Shtirlitz [24]

Answer:

a

   The  null hypothesis is  H_o :  \mu =  35 .1 \ million  \ shares

    The  alternative hypothesis  H_a  :  \mu  \ne  35.1\ million  \ shares

b

 The   95% confidence interval is  27.475   <  \mu < 37.925

Step-by-step explanation:

From the question the we are told that

      The  population mean is  \mu  = 35.1 \  million \ shares

      The  sample size is  n = 30

       The  sample mean is  \= x  =  32.7 \ million\    shares

       The standard deviation is  \sigma =  14.6 \ million\  shares

     

Given that the confidence level is  95\% then the level of significance is mathematically represented as

                  \alpha  = 100-95

                  \alpha  = 5\%

=>               \alpha  = 0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    The value is  Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as

                 E  =  Z_{\frac{\alpha }{2} } *  \frac{ \sigma }{\sqrt{n} }

substituting values

                E  =  1.96 *  \frac{ 14.6 }{\sqrt{30} }

                E  =  5.225

The 95% confidence interval confidence interval is mathematically represented as

              \= x  -E  <  \mu <  \= x  +E

substituting values

               32.7 - 5.225   <  \mu < 32.7 + 5.225

                27.475   <  \mu < 37.925

       

6 0
2 years ago
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