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3 years ago

Calculate the mean of the data set

Mathematics

1 answer:

barxatty [35]3 years ago

8 0

Answer:

Step-by-step explanation:

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Jesse added two more numbers to his expression, but the sum did not change. What could the two new numbers be? Explain why the n

kenny6666 [7]

Answer:

0 and 0

Step-by-step explanation:

The only number that can be applied to the expression without changing the sum is 0, for example 5 + 10 = 15, adding 2 0's will be 0 + 5 + 10 + 0 = 15 :D

4 0

2 years ago

Read 2 more answers

It is estimated that 30% of households own a riding lawn mower. A sample of 17 households is studied. What is the standard devia

alina1380 [7]

Answer:

1.89 is the standard deviation of households who own a riding mower

Step-by-step explanation:

Let the random variable X denote the number of households owning a riding lawn mower. From the given information, X will be a Binomial random variable with parameters; n = 17 and p = 30% = 0.3

The standard deviation of X;

$\sqrt{n*p*(1-p)}$

$\sqrt{17*0.3*(1-0.3)} =1.89$

7 0

2 years ago

The 7th graders in the middle school are going on a field trip to the aquarium. They will spend 4 ¼ hours walking inside of the

Firlakuza [10]

Answer:

The answer is 5.

Step-by-step explanation:

17 / 4 + 3 / 4 =

(17 × 4) + (3 × 4)

4 × 4 = 80 / 16 =

80 ÷ 16

16 ÷ 16

= 5

Hope this helps!

6 0

3 years ago

HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r

lesya692 [45]

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression $2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)$

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

$= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\$

Then we find the LCM of the resulting function

$= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\= \frac{7x}{10} + 2\frac{1}{2}y+6\\$