What are two simpler problems for 7x38

Mathematics

2 answers:

siniylev [52]3 years ago

5 0

So half of 38 is 19 so 7x19=133 then double it so133+133=266

ra1l [238]3 years ago

3 0

here are 2 I think

14x17

7x30 + 7x8

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the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width

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Width = 12 inches

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Step-by-step explanation:

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As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

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Now, According to the Question :

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