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evablogger [386]
4 years ago
7

What is $16.50 x 7%​

Mathematics
1 answer:
Alexus [3.1K]4 years ago
4 0

Answer:

1.155

Step-by-step explanation:

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YO PLEASE HELP ME ASAP!!! Which explicit function defines this arithmetic sequence?
BartSMP [9]

Answer:

351

Step-by-step explanation:

d

6 0
3 years ago
A line contains the points (4,4) and (5,2). What is the equation of the line
Mariulka [41]

Answer:y=-2/1x+12

Step-by-step explanation:

To find slope you need to use slope formula (y2-y1)/(x2-x1)

(2-4)/(5-4)

-2/1 is our slope

Now we need the y-int

Y=-2/1x+b

Take one of the given points and apply it to our equation

2=-2/1(5)+b

2=-10/1+b

2=-10+b

Add 10 to each side

12=b

Our final equation is

y=-2/1x+12

8 0
3 years ago
Two teams A and B play a series of games until one team wins three games. We assume that the games are played independently and
Olenka [21]

Answer:

The probability that the series lasts exactly four games is 3p(1-p)(p^{2} + (1 - p)^{2})

Step-by-step explanation:

For each game, there are only two possible outcomes. Either team A wins, or team A loses. Games are played independently. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

We also need to know a small concept of independent events.

Independent events:

If two events, A and B, are independent, we have that:

P(A \cap B) = P(A)*P(B)

What is the probability that the series lasts exactly four games?

This happens if A wins in 4 games of B wins in 4 games.

Probability of A winning in exactly four games:

In the first two games, A must win 2 of them. Also, A must win the fourth game. So, two independent events:

Event A: A wins two of the first three games.

Event B: A wins the fourth game.

P(A):

A wins any game with probability p. 3 games, so n = 3. We have to find P(A) = P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(A) = P(X = 2) = C_{3,2}.p^{2}.(1-p)^{1} = 3p^{2}(1-p)

P(B):

The probability that A wins any game is p, so P(B) = p.

Probability that A wins in 4:

A and B are independent, so:

P(A4) = P(A)*P(B) = 3p^{2}(1-p)*p = 3p^{3}(1-p)

Probability of B winning in exactly four games:

In the first three games, A must win one and B must win 2. The fourth game must be won by 2. So

Event A: A wins one of the first three.

Event B: B wins the fourth game.

P(A)

P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(A) = P(X = 1) = C_{3,1}.p^{1}.(1-p)^{2} = 3p(1-p)^{2}

P(B)

B wins each game with probability 1 - p, do P(B) = 1 - p.

Probability that B wins in 4:

A and B are independent, so:

P(B4) = P(A)*P(B) = 3p(1-p)^{2}*(1-p) = 3p(1-p)^{3}

Probability that the series lasts exactly four games:

p = P(A4) + P(B4) = 3p^{3}(1-p) + 3p(1-p)^{3} = 3p(1-p)(p^{2} + (1 - p)^{2})

The probability that the series lasts exactly four games is 3p(1-p)(p^{2} + (1 - p)^{2})

8 0
3 years ago
A consumer organization that evaluates new motorcycles customarily reports the number of major defects in each motorcycle examin
koban [17]

Answer:

a) F(2)=0.30

b)P(X>3)=0.7

c)P(2≤X≤5)=0.67

d)P(2<X<5)=0.71

Step-by-step explanation:

a) F(2)=P(X≤2)=0.30

F(2) is given in the probability distribution

b) P(X>3)=1-P(X≤2)=1-F(2)=1-0.3=0.7

P(X>3)=0.7

c)P(2≤X≤5)=?

As we know that P(a≤X≤b)=F(b)-F(a)=P(X≤b)-P(X≤a)

So,

P(2≤X≤5)=P(X≤5)-P(X≤2)=F(5)-F(2)=0.97-0.3=0.67

P(2≤X≤5)=0.67

d)P(2<X<5)=P(1≤X≤4)=P(X≤4)-P(X≤1)=F(4)-F(1)=0.91-0.2=0.71.

P(2<X<5)=0.71

5 0
3 years ago
Lengths of segments
mina [271]

Answer:

Triangles:

10 m, 21 m, 29 m

10 m, 29 m, 37 m

Not triangles:

10 m, 14 m, 29 m

10 m, 29 m, 40 m

Step-by-step explanation:

For a triangle to exist, the sum of any two sides of a triangle must be greater than that of the third side.

Let us check each of the options.

Option 1: 10 m, 14 m, 29 m

The sum of lengths 10 m and 14 m must be greater than 29 m.

10 + 14 = 24 < 29

So, this is not a triangle.

Option 2: 10 m, 21 m, 29 m

10 + 21 = 31 > 29

21 + 29 = 50 > 10

29 + 10 = 39 > 21

Therefore, it is a triangle.

Option 3: 10 m, 29 m, 37 m

10 + 29 = 39 > 37

29 + 37 = 66 > 10

37 + 10 = 47 > 29

Therefore, it is a triangle.

Option 4: 10 m, 29 m, 40 m

10 + 29 =39 < 40

So, this is not a triangle.

4 0
3 years ago
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