Answer:
(48 m^12)/n^8
Step-by-step explanation:
Simplify the following:
3 ((2 m^3)/(n^2))^4
Multiply each exponent in (2 m^3)/(n^2) by 4:
3×2^4 m^(4×3) n^(-2×4)
4 (-2) = -8:
3×2^4 m^(4×3) n^(-8)
4×3 = 12:
(3×2^4 m^12)/(n^8)
2^4 = (2^2)^2:
(3 (2^2)^2 m^12)/(n^8)
2^2 = 4:
(3×4^2 m^12)/(n^8)
4^2 = 16:
(3×16 m^12)/(n^8)
3×16 = 48:
Answer: (48 m^12)/n^8
Anwer:
Theres not enough info. given to solve the prob, post more info.
Step-by-step explanation:
No. You can’t add the two lower numbers up to make the bigger number making them not a triangle.
Two negatives <em>do not </em>equal a positive when adding. If you're in debt and you add more debt, does that get you out of debt?
Two negatives <em>do </em>equal a positive when you're multiplying them together though. This makes sense if you imagine multiplication as squishing or stretching a particular number on the number line. For example, imagine multiplying 2 x 1/2 as <em>squishing </em>the number 2 two times closer to 0. When you multiply 2 by a negative number, say, -1, you squish it so far down that you <em>flip it to the negative side of the number line</em>, bringing it to -2. You can imagine a similar thing happening if you multiply a number like -4 by -2. You squish -4 down to zero, and then <em>flip it to the positive side</em> and stretch it by a factor of 2, bringing it to 8.
