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DENIUS [597]
2 years ago
15

A line contains the points (4,4) and (5,2). What is the equation of the line

Mathematics
1 answer:
Mariulka [41]2 years ago
8 0

Answer:y=-2/1x+12

Step-by-step explanation:

To find slope you need to use slope formula (y2-y1)/(x2-x1)

(2-4)/(5-4)

-2/1 is our slope

Now we need the y-int

Y=-2/1x+b

Take one of the given points and apply it to our equation

2=-2/1(5)+b

2=-10/1+b

2=-10+b

Add 10 to each side

12=b

Our final equation is

y=-2/1x+12

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Answer:

y =  (- \frac{16}{9})x +  \frac{40}{9}is the slope intercept form for 16x+9y=40

Step-by-step explanation:

Here, the given equation is 16 x +  9 y = 40

Now, the slope intercept form of an equation is y = mx + c,

here m = slope of the equation,  b  =  y - intercept

So, now 16x +  9y = 40 on simplification gives

9y  = 40 - 16x

or y = \frac{40 - 16x}{9}  = \frac{40}{9}   - \frac{16x}{9}

or, y =  (- \frac{16}{9})x +  \frac{40}{9}is the slope intercept form of the given equation.

Here, m = (-16/9) and y- intercept = 40/9

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Step-by-step explanation:

(Sorry if im wrong)

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Step-by-step explanation:

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