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True [87]
3 years ago
6

Given: △OKE∼△VDE Prove: EK/EO = ED/EV

Mathematics
1 answer:
harkovskaia [24]3 years ago
6 0

Answer:

The proof is below.

Step-by-step explanation:

Given two triangles similar.

we have to prove that ratio \frac{EK}{EO}=\frac{VE}{ED}

As, △OKE∼△VDE

∴ their corresponding sides are in same proportion.

\frac{OK}{VD}=\frac{EK}{ED}=\frac{OE}{VE}

⇒ \frac{EK}{ED}=\frac{EO}{VE}

⇒ [tex}\frac{EK}{EO}=\frac{VE}{ED}[/tex]

Hence Proved.

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Square root of -1 = 1. Math test
pantera1 [17]

Answer:

false. the sqrt of -1 = i

Step-by-step explanation:

6 0
3 years ago
Show work ! please !!!!!!
Law Incorporation [45]

Sin A =  opp/hyp = 4/5

Cos A = adj/hyp =  3/5

Tan A = opp/adj =  4/3

Cos 27 = 0.8910065...  --> 0.89

You can just plug that into your graphing calculator, just make sure the degree mode is on.

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2 years ago
90 is n multiplied by 123 write equation (IXL)
Keith_Richards [23]

90 = n * 123

n = 90 / 123

n = 0.731707317073170...



7 0
2 years ago
Read 2 more answers
Please help me. Factor. 5x^+23x+26
Alexus [3.1K]
<span>Algebra Calculator | Latest | Discuss | About | Help | Translation</span>

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Skip Ad <span> <span> <span> <span> </span> <span>
</span></span></span></span> <span><span> 5x2-23x=-26</span> </span>Two solutions were found :<span><span>  x = 2 </span><span>  x = 13/5 = 2.600
</span></span>

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                     5*x^2-23*x-(-26)=0 

Step by step solution :Skip Ad
<span> Step  1  :</span><span>Equation at the end of step  1  :</span><span> (5x2 - 23x) - -26 = 0 </span><span> Step  2  :</span>Trying to factor by splitting the middle term

<span> 2.1 </span>    Factoring <span> 5x2-23x+26</span> 

The first term is, <span> <span>5x2</span> </span> its coefficient is <span> 5 </span>.
The middle term is, <span> -23x </span> its coefficient is <span> -23 </span>.
The last term, "the constant", is <span> +26 </span>

Step-1 : Multiply the coefficient of the first term by the constant <span>  5 • 26 = 130</span> 

Step-2 : Find two factors of  130  whose sum equals the coefficient of the middle term, which is  <span> -23 </span>.

<span><span>       -130    +    -1    =    -131 <span>
</span> </span> <span>       -65    +    -2    =    -67 <span>
</span> </span> <span>       -26    +    -5    =    -31 <span>
</span> </span> <span>       -13    +    -10    =    -23    That's it</span></span>
4 0
3 years ago
Polynomial function in standard form with zeros 5,-4,1
Oksanka [162]

Answer:

\boxed{\sf \ \ \  x^3-2x^2-19x+20 \ \ \  }

Step-by-step explanation:

hello,

by definition we can write

(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

hope this helps

5 0
3 years ago
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