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ch4aika [34]
3 years ago
14

56 + 42 = 7(8 + 6) Yes No

Mathematics
2 answers:
bazaltina [42]3 years ago
8 0

7(8+6)

8+6 = 14

7(14)

98

56 + 42 = 98

98 = 98

Answer is Yes.


Hope this helps you! (:

-Hamilton1757

My name is Ann [436]3 years ago
7 0

56 + 42 = 7(8 + 6)

use distributive property: a(b + c) = ab + ac

56 + 42 = (7)(8) + (7)(6)

56 + 42 = 56 + 42

Answer: YES

Other method:

Use PEMDAS:

L = 56 + 42 = 98

R = 7(8 + 6) = 7(14) = 98

L = R

Answer: YES

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Answer:

The p-value of the test is 0.0018, which means that for a level of significance higher than this, there is sufficient evidence to claim that less than 50% of Internet users get their health questions answered online.

Step-by-step explanation:

Test the claim that less than 50% of Internet users get their health questions answered online.

At the null hypothesis, we test that 50% of Internet users get their health questions answered online, that is:

H_0: p = 0.5

At the alternate hypothesis, we test that this proportion is less than 50%, that is:

H_a: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5

A random sample of 1318 Internet users was asked where they will go for information the next time they need information about health or medicine; 606 said that they would use the Internet.

This means that n = 1318, X = \frac{606}{1318} = 0.4598

Test statistic:

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z = -2.92

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.4598, which is the p-value of z = -2.92.

Looking at the z-table, z = -2.92 has a p-value of 0.0018.

The p-value of the test is 0.0018, which means that for a level of significance higher than this, there is sufficient evidence to claim that less than 50% of Internet users get their health questions answered online.

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3 years ago
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shutvik [7]

Answer:

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b) The Z value of 0.74 corresponds to 77% service probability.

Step-by-step explanation:  

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The Z value of 0.74 corresponds to 77% service probability.

4 0
3 years ago
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