Answer:
tan²A
Step-by-step explanation:
1+tan²A/1+cot²A Simplify 1+tan²A first
sec²A/1+cot²A Now simplify 1+cot²A
sec²A/csc²A Simplify sec²A and csc²A
/
Simplify the fraction
sin²A/cos²A = tan²A
If this answer is correct, please make me Brainliest!
Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.
Answer:
x = 1. x = - 5/4
(Plz excuse me if it's wrong lol)
A rhombus diagonals form right angles. The diagonals also cut in half the angles
use cosine: cos38 = 
a = 20cos38
a=15.8
Answer:
1.306
Step-by-step explanation:
1.3 is bigger than
1.03
