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2 years ago

What is the area of a triangle when the sides are 17, 8 and 9

Mathematics

1 answer:

sleet_krkn [62]2 years ago

7 0

Answer:

ok so to solve this you need to do base x height then divide that by 2

Step-by-step explanation:

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Help! Will give brainliest and 5 stars rating and thanks

Morgarella [4.7K]

Answer:

x < -4 or x > 8

On a number line, make two arrows:

1) going towards left from -4 with an open circle at -4

2) going towards right from 8 with an open circle at 8

Step-by-step explanation:

l -4 +2x l -3 > 9

l -4 +2x l > 12

l 2x - 4 l > 12

2x - 4 > 12

2x > 16

x > 8

-2x + 4 > 12

-2x > 8

x < -4

On a number line, make two arrows:

1) going towards left from -4 with an open circle at -4

2) going towards right from 8 with an open circle at 8

8 0

3 years ago

Read 2 more answers

Find the output, y, when the input, x, is -9. Y = ?

Monica [59]

When X = -9 Y = 1 you can find this by going to -9 on the x axis and finding where the line is there

5 0

3 years ago

Solve 0 = -1.8y + 0.72. What is y = to? 1.0.4 2.-0.4 3.0.8 4.1.8

PIT_PIT [208]

Answer:

0.4

Step-by-step explanation:

just solve it like an equation.

4 0

2 years ago

Read 2 more answers

Dada la ecuacion 25x2 + 4y2 = 100, determina las coordenadas de los vertices, focos, las longitudes de los respectivos ejes mayo

Likurg_2 [28]

Answer:

The given equation is

$25x^{2} +4y^{2}=100$

Which represents an elipse.

To find its elements, we need to divide the equation by 100

$\frac{25x^{2} +4y^{2} }{100} =\frac{100}{100} \\\frac{x^{2} }{4} +\frac{y^{2} }{25} =1$

Where $a^{2} =25$ and $b^{2}=4$ . Remember that the greatest denominator is $a$ , and the least is $b$ . So, we extract the square root on each equation.

$a=5$ and $b=2$ .

In a elipse, we have a major axis and a minor axis. In this case, the major axis is vertical and the minor axis is horizontal, that means this is a vertical elipse.

The length of the major axis is $2a=2(5)=10$ .