Answer: a) 0.84 b) 0.67 c) 1.28
Step-by-step explanation:
Using the standard normal distribution table for z-value , we have
(a) The value of
would result in a 80% one-sided confidence interval : 
(b) The value of
would result in a 85% one-sided confidence interval : 
(c) The value of
would result in a 90% one-sided confidence interval : 
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➷ Find the original multiplier that would have reduced the price by 38%
multiplier is 0.78
Divide the value by this multiplier:
279/0.78 = 357.69
The original price was $357.70
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Answer:
D
Step-by-step explanation:
-9x-27+12 = -6x-15-3x
0=0
D) the equation has infinitely many solutions
Answer:2x+6
Step-by-step explanation:
Answer:
length = 60 foot, width = 30 foot
Step-by-step explanation:
Area of rectangular part, A = 1800 ft²
Cost of fencing three sides is $ 6 per foot and cost of one side fencing is $18 per foot.
Let the length of the rectangle is l and the width of the rectangle is W.
Area = Length x width
A = L x W
1800 = L x W ...... (1)
Total cost of fencing, C = 6 x ( L + W + L) + 18 x W
C = 6 (2L + W) + 18 W
C = 12 L + 24 W
Substitute the value of W from equation (1),
in equation (2)


Differentiate both sides with respect to L:

Put it equal to zero for maxima and minima

L = 60 foot
and W = 30 foot
So, the costing is minimum for length = 60 foot and the width = 30 foot.