We are assuming that p is the price of the house and that q is the number of the houses.
The points given (q,p) , therefore, are:
(20 , 540000) and (50 , 450000)
The general form of the linear straight line is:
y = mx+c where m is the slope and c is the y-intercept.
(1) Calculating the slope:
The formula used to calculate the slope is:
m = (y2-y1) / (x2-x1) where:
y2 is the y-coordinate of the second point = 450000
y1 is the y-coordinate of the first point = 540000
x2 is the x-coordinate of the second point = 50
x1 is the x-coordinate of the first point = 20
Therefore:
m = (450000-540000) / (50-40) = -3000
(2) Calculating the y-intercept:
After getting the slope, the equation now is:
y = -3000x + c
To get the value of thec, use any point that belongs to the line and substitute with it in the equation above. I will use the point (20, 540000).
y = -3000 + c
540000 = -3000(20) + c
c = 540000 + 3000(20) = 600000
Based on the above calculations, the equation of the line is:
y = -3000x + 600000
There are 12 more of white and blue cars than silver and red cars
Step-by-step explanation:
Step 1 :
Number of black cars counted by Ed = 23
Number of red cars counted by Ed = 9
Number of blue cars counted by Ed = 17
Number of white cars counted by Ed = 25
Number of silver cars counted by Ed = 21
We need to determine how many more white and blue cars are there than silver and red cars
Step 2 :
Total of white and blue cars = 25 + 17 = 42 cars
Total of sliver and red cars = 21 + 9 = 30 cars
Difference = 42 - 30 = 12 cars
Hence there are 12 more of white and blue cars than silver and red cars
Step 3 :
Answer :
There are 12 more of blue and white cars than red and silver cars
Answer:
B
Step-by-step explanation:
SA/V = 300m^2/500m^3 -------- m^2 cancel out and so d othe 100
we get 3/(5m)
Sooo, I guess that's equal to 3/5 1/m and 1/m is m^-1 so we have (B)
