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Citrus2011 [14]
3 years ago
14

It is estimated that approximately 8.26% Americans are afflicted with diabetes. Suppose that a certain diagnostic evaluation for

diabetes will correctly diagnose 94.5% of all adults over 40 with diabetes as having the disease and incorrectly diagnoses 3.5% of all adults over 40 without diabetes as having the disease. a) Find the probability that a randomly selected adult over 40 does not have diabetes, and is diagnosed as having diabetes (such diagnoses are called "false positives").
Mathematics
1 answer:
sweet [91]3 years ago
8 0

Answer:

0.032109

Step-by-step explanation:

From the given information

the estimate of those afflicted with diabetes = 0.0826

the estimate of those that are not afflicted with diabetes = 1 - 0.0826

= 0.9174

From adult with 40

Pr (correct diagnoses) = 0.945

Pr(incorrect diagnoses) = 0.035

The objective that the probability of a randomly selected adult which is over 40 and does not have diabetes, and is diagnosed as having diabetes (false positive) is =  0.9174 × 0.035

= 0.032109

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amm1812
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<span>a^2 + b^2 is = to c^2</span>
8 0
3 years ago
John and Emily are brother and sister. John has as many brothers as sisters, and Emily has twice as many brothers as sisters. Ho
spin [16.1K]

Answer:

4 boys, 3 girls

Step-by-step explanation:

brothers of John ⇒ x

sisters of John ⇒ y

John has as many brothers as sisters:

  1. x = y

brothers of Emily ⇒ x + 1 (Emily have the same amount of brother as John, plus one (John))

sisters of Emily ⇒ y -1 (Emily have the same amount of sister as John, minus one (herself))

Emily has twice as many brothers as sisters:

  1. 2 (y-1) = x+ 1

Now we have a system of 2 equations and 2 variables

x=y (I)

2y - 2 = x + 1 (II)

____________

Replace x in equation II

2y - 2 = y + 1

2y - y = 2 + 1

y = 3

____________

Replace y in equation I

x = y = 3

That mean that John have 3 brothers plus himself, there is 4 boys in the family and John have 3 sister, so there is 3 girls in the family

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3 years ago
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vovikov84 [41]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
For this question, consider the function f (x ) = -2x 2 + 8x + 3.
ololo11 [35]

f' = -4x+8=0 => x=2

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8 0
3 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
3 years ago
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