The distributive property....u r basically multiplying the number outside of the parenthesis by everything inside the parenthesis...this gets rid of the parenthesis.

3(-4x + 8)...distribute the 3 thru the parenthesis
(3 * -4x) + (3 * 8) ...take that 3 and multiply it by every number in the parenthesis..to get rid of the parenthesis
-12x + 24 <===

4(x - 6y) =
(4 * x) - (4 * 6y) =
4x - 24y <===

6(5 - q) =
(6 * 5) - (6 * q) =
30 - 6q <===

1/2(c - 8) =
(1/2 * c) - (1/2 * 8) =
1/2c - 4 <===

-3(5 - b) =
(-3 * 5) - (-3 * b) =
-15 - (-3b) =
-15 + 3b <===

(d + 2)(-7)....re-arrange
-7(d + 2) =
(-7 * d) + (-7 * 2) =
-7d + (-14) =
-7d - 14 <===

3 0

3 years ago

Csc\theta -cot\theta =\frac{sin}{1+cos\theta }

Inga [223]

Answer:

Step-by-step explanation:

Left Hand Side

Change to sin(theta) and cos(theta)

csc(theta) = 1/sin(theta)

cot(theta) = cos(theta)/sin(theta)

1/sin(theta) - cos(theta)/sin(theta) Put over Sin(theta) Common denominator

[1 - cos(theta)] / sin(theta) Multiply numerator and denominator by 1 + cos(theta)

(1 - cos(theta)(1 + cos(theta) ) / sin(thata)*(1 + cos(theta))

(1 + cos(theta)(1 - cos(theta)) = 1 - cos^2(theta)

sin^2(theta) / (sin(theta)* ( 1 + cos(theta)

sin(theta) / (1 + cos(theta) )

Right hand Side.

See Above.

4 0

3 years ago