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Sauron [17]
3 years ago
8

A regular polygon of 2 k + 1 sides has 140 as size of each interior angle find K​

Mathematics
1 answer:
natita [175]3 years ago
4 0
Hope this can help.

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Please help me with this question
Triss [41]

Answer:

B) We would know Mrs. Mallard's thought about her husband's death.

Step-by-step explanation:

If it were told from Mrs. Mallard's point of view, then we would be able to know what she is thinking and feeling at that time.

5 0
4 years ago
An airplane is flying in still air with an airspeed of 475 miles per hour. The plane is climbing at an angle of 16°. Find the ra
Serhud [2]

Answer:

130.9 miles per hour.

Step-by-step explanation:

sine 16 = x / 475 where x = rate of gaining altitude.

x = 475 sin 16

= 130.9 miles per hour.

6 0
3 years ago
Graph the equation y= 1/2x +3
PolarNik [594]
Find some graphing paper and graph away..
i.e. Sub in x = 0 and find what y = ?
y = 1/2(0) + 3
y = 3
So we know the coordinate (0,3)

When x = 4 , y = ?
y = 1/2(4) + 3
y = 4/2 + 3
y = 2 + 3
y = 5
So we know another coordinate (4, 5)

When x = -4, y = ?
y = 1/2(-4) + 3
y = -4/2 + 3
y = -2 + 3
y = 1
So we know another coordinate (-4, 1)

Putting it all together, the coordinates: (-4, 1) , (0, 3) and (4, 5) should be plenty sufficient to graph and then draw a line of best fit connecting them.
4 0
3 years ago
Please help math question WILL MARK AS BRAINLIEST IF CAN PLEASE HELP!!
alukav5142 [94]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
3 years ago
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