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scoundrel [369]
2 years ago
15

One solution each is given for four quadratic equations. Assuming that each quadratic equation has two solutions, what is the se

cond solution
for each equation?
I = - 4 + 51
I = 4 - 5
I = 5 + 4i
I = -5 - 4
I = 4 + 51
H
II
5 - 4
II
- 51
Reset
Next

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
5 0

Answer:

5+4i=4i+5

5i-4=-4+5i

-5i-4=-4-5i

Step-by-step explanation:

5+4i=4i+5

5i-4=-4+5i

-5i-4=-4-5i

Find the two that are the same with the terms swiched around and you get the answer.

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