1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scoundrel [369]
2 years ago
15

One solution each is given for four quadratic equations. Assuming that each quadratic equation has two solutions, what is the se

cond solution
for each equation?
I = - 4 + 51
I = 4 - 5
I = 5 + 4i
I = -5 - 4
I = 4 + 51
H
II
5 - 4
II
- 51
Reset
Next

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
5 0

Answer:

5+4i=4i+5

5i-4=-4+5i

-5i-4=-4-5i

Step-by-step explanation:

5+4i=4i+5

5i-4=-4+5i

-5i-4=-4-5i

Find the two that are the same with the terms swiched around and you get the answer.

You might be interested in
If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta​
Ivahew [28]

Step-by-step explanation:

<h3>Need to FinD :</h3>

  • We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.

\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

  • PQ = Opposite side
  • QR = Adjacent side
  • RP = Hypotenuse
  • ∠Q = 90°
  • ∠C = θ

As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}

Since, we know that,

  • cosθ = 5/13
  • QR (Adjacent side) = 5
  • RP (Hypotenuse) = 13

So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}

\rule{200}{3}

\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}

Where,

  • Opposite side = 12
  • Hypotenuse = 13

Therefore,

\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}

  • By substituting the values, we get,

\rule{200}{3}

\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}

∴ Hence, the required answer is 17/7.

6 0
2 years ago
If DEF ~= PQR, which congruences are true by CPCTC? Select all that apply.
tatyana61 [14]

Answer:

A, C, E, F

Step-by-step explanation:

6 0
3 years ago
2-2=<br> Whats the answer
lutik1710 [3]

Answer:

0

Step-by-step explanation:

because the answer to this is 0

7 0
3 years ago
Read 2 more answers
What is the formula that relates circumference and radius?
cestrela7 [59]
B is the correct answer choice I know it
6 0
3 years ago
Find the sum of interior angles in a 5 sided polygon
densk [106]

Answer:

540 degrees

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • 144 students enter a spelling bee,but only 1/6 of the group will make into the semi-final round, and only 2/3 that group will ma
    13·1 answer
  • Explain how to estimate 368+231 two different ways
    13·2 answers
  • Factor completely:<br><br> <img src="https://tex.z-dn.net/?f=3x%5E3%2B21x%5E2%2B36x" id="TexFormula1" title="3x^3+21x^2+36x" alt
    12·1 answer
  • Plug the numbers in that you know, and solve for the height:
    10·2 answers
  • You have c pounds of cashews and 2.7 pounds of peanuts you have 6 pounds of nuts altogether solv the equation c+2.7 =6 to find h
    9·1 answer
  • Can someone please help?​
    8·2 answers
  • - (4W + 6k)<br> Your answer
    9·1 answer
  • Please help me I do not understand this!​
    6·2 answers
  • What ordered pair is -3x + 4y =14
    15·1 answer
  • Can you help me with this question??
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!