Answer:

Step-by-step explanation:
You have the following quadratic equation given in the problem:

You must make the equation equal to zero, as following:

Add like terms:

Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:

Answer:
it's the last one i mean 4&1/4
Answer:
try 5
Step-by-step explanation:
PEMDAS.
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Lets apply that here.
72-[(3x2^3)+48]
So first we start with (3x2^3)
2^3=8
3*8=24
now we do 24+48 which equals 72
now we have 72-72 which equals zero.
So
72-[(3x2^3)+48] = 0
To find area of square one :-
Given :
To find :
We know :
Area of square = side²
Therefore:-
→Area of square = 9²
→Area of square = 9 × 9
→Area of square = 81 (unit)²
To find area of square two :-
Given :
To find :
We know :
Area of square = side²
Therefore:-
→Area of square = 11²
→Area of square = 11 × 11
→Area of square = 121 (unit)²
Now it's clearly visible that the whole figure is also. a square .
Therefore AE = CP
Which means area of square three = 81 (unit)²
Now area of shaded figure :-
- Area of square one + Area of square two + Area of square three
- 81 + 81 + 121
- 283 (unit)²