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Inga [223]
3 years ago
14

Use factoring to solve the quadratic equation x2 − 2x − 3 = 12.

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer:

x = -3 and x = 5

Step-by-step explanation:

x² − 2x − 3 = 12

x² − 2x − 3  - 12 = 0

x² − 2x − 15 = 0

Product = -15

sum = -2

Factors  are: 3, -5

So the equation becomes;

x² − 2x − 15 = 0

x² + 3x - 5x − 15 = 0

(x² + 3x) - (5x + 15) = 0

x(x + 3) - 5(x + 3) = 0

(x + 3)(x - 5) = 0

∴ (x + 3) = 0

    x = -3  

          or

   (x - 5) = 0

    x = 5

melomori [17]3 years ago
7 0

Answer:

x_1=5\\x_2=-3

Step-by-step explanation:

You have the following quadratic equation given in the problem:

x^{2}-2x-3=12

You must make the equation equal to zero, as following:

x^{2}-2x-3-12=0

Add like terms:

 x^{2}-2x-15=0

Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:

(x-5)(x+3)=0\\x_1=5\\x_2=-3

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alukav5142 [94]
In this problem, we need to plug in the given x values for f(x)=0 and find a and b.

When we plug in 1, we get: 2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0

Simplify:
2 - 5 - 14 + a + b = 0
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We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0
512 - 320 - 224 + 4a + b = 0
- 32 + 4a + b = 0
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Now we have our second one. We can combine them:
a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1: - a - b = - 17 \\ 4a + b = 32

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So, the answers are a=5 and b=12 .
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