Can someone help me find the answers to this question

Mathematics

1 answer:

Luden [163]3 years ago

7 0

Ok so right triangle Angels and finding the ratio umm in my calculation I’m coming up with C

You might be interested in

Write each equation in slope-intercept form (3,4); and (-6,-2)

Alborosie

Answer:

y = 2/3x + 2

Step-by-step explanation:

Slope intercept form is y=mx+b where m is the slope and b is the y intercept.

Given 2 points you can find the slope using (y-y1)/(x-x1)

m = (-2-4)/(-6-3) = -6/-9 = 2/3

To find b use one of the points and m and plug into the slope intercept form and then solve for b.

y=mx+b

4=2/3(3) + b

4=2 + b

b=2

Now we can write the final equation as : (plug m and b back in)

y = 2/3x + 2

7 0

2 years ago

Read 2 more answers

Subtract these polynomials

SCORPION-xisa [38]

So I couldn’t do square roots so I had to take a photo

4 0

3 years ago

Read 2 more answers

Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop

xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

f(x)=log (3 x) +5 x²

$f'(x)=\frac{1}{3x}+10 x$

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

$x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248$

$x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012$

$x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057$

$x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052$