All categories

3 years ago

Can someone help me find the answers to this question

Mathematics

1 answer:

Luden [163]3 years ago

7 0

Ok so right triangle Angels and finding the ratio umm in my calculation I’m coming up with C

You might be interested in

Solve this identifying holes, vertical asymptotes, and horizontal asymptotes for

USPshnik [31]

$x^2+7x+12=x^2+4x+3x+12=x(x+4)+3(x+4)=(x+4)(x+3)\\\\-x^2-3x+4=-(x^2+3x-4)=-(x^2+4x-x-4)\\\\=-[x(x+4)-1(x+4)]=-(x+4)(x-1)\\\\f(x)=\dfrac{x^2+7x+12}{-x^2-3x+4}=\dfrac{(x+4)(x+3)}{-(x+4)(x-1)}\\\\\text{Vertical asymptotes:}\\\\(x+4)(x-1)=0\iff x+4=0\ \vee\ x-1=0\\\\\boxed{x=-4\ and\ x=1}\\\\\text{Horizontal asymptotes:}$

$\lim\limits_{x\to\pm\infty}\dfrac{x^2+7x+12}{-x^2-3x+4}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\dfrac{7}{x}+\dfrac{12}{x^2}\right)}{x^2\left(-1-\dfrac{3}{x}+\dfrac{4}{x^2}\right)}=\dfrac{1}{-1}=-1\\\\\boxed{y=-1}$

6 0

3 years ago

What is the solution of -83=b/4

Gre4nikov [31]

I believe it is -332.
(-83= -332 ÷ 4)

6 0

3 years ago

Can somebody helppp !!! ???

viva [34]

Answer:

try b

Step-by-step explanation:

7 0

3 years ago

What is the value of f(3) in the function below?

Pani-rosa [81]

Answer:

B.3/2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The equation y 16t 2 18t 405 describes the height in feet of a ball thrown downward at 18 feet per second from a height of 405 f

kumpel [21]

Answer:

Ball hits the ground after 4.5 sec

Step-by-step explanation:

Let a -1, so that the leading coefficient is positive

So our quadratic is

$-1 \times (16t^2 +18t -405)$

The key coefficients of two binomial variables can be 1 and 16, or 2 and 8, or 4 and 4, for the leading coefficient of 16.

Yet they can't actually be 4 and 4 because the linear (x) term coefficient has to be a multiple of 4, which it isn't and leading coefficients 1 and 16 on the binomial factors is not likely.

So, 2 and 8 taken as the leading coefficients of two binomial factors.

For constant 405, possible factorizations are $(81\times 5, 27 \times 15, 9 \times 45).$

$(16t^2 +18t -405) = (8t + 45) (2t - 9)$

Taking first factor, thus we find negative value for given time t. But second time equivalent to zero gives the value of 4.5 for t

Thus ball hits the ground after 4.5 sec

3 0

3 years ago