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Mnenie [13.5K]
3 years ago
13

4. What key features of a quadratic graph can be identified and how are the graphs affected when the constants or coefficients a

re added to the parent quadratic equations? Compare the translations to the graph of linear function. Create examples of your own to explain the differences and similarities.

Mathematics
2 answers:
aev [14]3 years ago
7 0

Answer:

The parent function of a quadratic function is

y=x^{2}

Now, if we add units we can move this function upwards, downwards leftwards and rightwards.

If we add a positive number to the x-variable, then the graph will move to the left.

If we add a negative number to the x-variable, then the graph will move to the right.

If we add a positive number to y-variable, then the graph will move upwards.

If we add a negative number to y-variable, then the graph will move downwards.

So, if we have the function

y=(x+3)^{2}-5

We would now that this functions is a parent function moved 3 units leftwards and 5 units downwards, that's how you deduct the translations.

Now, if we compare the rules we use before with linear function, there's no distinction between horizontal and vertical movements, because if we add to x-variable, then y-variable will be also affected.

For example, consider the parent function y=x

If we transform it to y=x+1, then the whole line will move up 1 unit, or it will move to the left 1 unit, it's the same. The images attached show this.

The second image attached show the transformation applied to the quadratic function. Notice the difference between the linear function and the quadratic function transformation.

natka813 [3]3 years ago
6 0
Standard quadratic equation .. y = a x^2 + b x + c 
<span>parabola 'a' not equal to zero </span>
<span>a<0 parabola opens downward </span>
<span>a>0 parabola opens upward </span>
<span>when |a| >>0 the parabola is narrower </span>
<span>when |a| is close to zero , the parabola is flatter </span>

<span>when the constant is varied it only effects the vertical position of the parabola , the shape remains the same</span>
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What is the balance after 15 years in a savings account that earns 2% interest compounded bimonthly when the initial deposit is
Ierofanga [76]

Answer:

$1348.07

Step-by-step explanation:

Hello!

<h3>Compound Interest Formula: A = P(1 + \frac rn)^{nt}</h3>
  • A = Account Balance
  • P = Principle/Initial Amount
  • r = Rate of Interest (decimal)
  • n = Number of times compounded (per year)
  • t = Number of Years

<h3>Given Information</h3>
  • Account Balance = ?
  • Principle Amount = $1000
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Why is the Rate 0.02?

This is because we are gaining money, so the multiplier should be greater than 1. We already added 1, which is 100% so you simply add the 0.02 for the extra 2%.

  • Number of times compounded per year = 6

This is because it is being compounded bi-monthly, or once every 2 months. 12 months divided by 2 months is 6 months, so 6 times a year.

  • Number of years = 15

<h2>Solve </h2>

Solve by plugging in the given values into the formula.

  • A = P(1 + \frac rn)^{nt}
  • A = 1000(1 + \frac {0.02}{6})^{6*15}
  • A = 1000(1 + 0.00333...)^{90}
  • A = 1000(1.00333...)^{90}
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This is really close to the first option, and since there is rounding involved with the repeating decimal, the first option should be correct.

The answer is $1348.07.

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2 years ago
Alice says that all the factors of 8 are even.
Rom4ik [11]
1 is not even yet it is a factor of 8. Alice is wrong.
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Manufacturers are testing a die to make sure that it is fair (has a uniform distribution). They roll the die 66 times and record
steposvetlana [31]

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We should reject H0

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Step-by-step explanation:

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3 years ago
Write an equation in slope-intercept form from the points (0, 3) and (-4,-1)
Bezzdna [24]

Answer:

y = x + 3

Step-by-step explanation:

Slope-intercept form is represented by the formula y = mx + b. We can write an equation in point-slope form first, then convert it to that form.

1) First, find the slope of the line. Use the slope formula  m = \frac{y_2-y_1}{x_2-x_1} and substitute the x and y values of the given points into it. Then, simplify to find the slope, or m:

m = \frac{(-1)-(3)}{(-4)-(0)} \\m = \frac{-1-3}{-4-0} \\m = \frac{-4}{-4} \\m = 1

Thus, the slope of the line must be 1.

2) Now, since we know a point the line intersects and its slope, use the point-slope formula y-y_1=m(x-x_1) and substitute values for m, x_1, and y_1. From there, we can convert the equation into slope-intercept form.

Since m represents the slope, substitute 1 in its place. Since x_1 and y_1 represent the x and y values of a point the line intersects, choose any one of the given points (either one is fine) and substitute its x and y values into the equation, too. (I chose (0,3).) Finally, isolate y to find the answer:

y-3=1(x-0)\\y-3 = x\\y = x + 3

8 0
3 years ago
(-6,8); perpendicular to y = -3/2x -1
UNO [17]

Answer:

y =  \frac{2}{3} x + 12

Step-by-step explanation:

y =  -  \frac{3}{2} x - 1

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Thus, gradient of given line=-  \frac{3}{2}.

The product of the gradients of perpendicular lines is -1.

(Gradient of line)(-3/2)= -1

Gradient of line

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Substitute m=\frac{2}{3} into y=mx+c:

y =  \frac{2}{3} x + c

To find the value of c, substitute a pair of coordinates.

When x= -6, y= 8,

8 =  \frac{2}{3} ( - 6) + c \\  \\ 8 =  - 4 + c \\ c = 8 + 4 \\ c = 12

Thus, the equation of the line is y =  \frac{2}{3} x + 12.

7 0
3 years ago
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