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Brilliant_brown [7]
3 years ago
14

Solve for x 4(x+7)+98x+45+7y=567

Mathematics
2 answers:
xxTIMURxx [149]3 years ago
5 0

Answer:

x  =  247/51  −  7y/102

Step-by-step explanation:

much love

<33

lmk if thats right ;)

Brrunno [24]3 years ago
4 0

Subtract 73  from both sides of the equation.

102x+7y=567-73

Subtract 7y from both sides of the equation.

102x=567-73-7y

Subtract 73 from 567

102x=494-7y

Divide each term by 102 and simplify

Divide each term 102x=494-7y by 102

\frac{102x}{102} =\frac{494}{102} +\frac{-7y}{102}

Cancel the greatest common factor which is 102x/102

\frac{102x}{102} =\frac{494}{102} +\frac{-7y}{102}

Divide x by 1x\frac{492}{102} +\frac{-7y}{102}

Cancel the common factor is 494 and 102

Factor 2 out of 494

x\frac{2(247)}{102} +\frac{-7y}{102}

Factor 2 out of 102

\frac{2*247}{2*51} +\frac{-7y}{102}

Cancel the common factor which is 2

Rewrite the expression.x=\frac{247}{51} +\frac{-7y}{102}

Move the negative in front of the fraction

\frac{247}{51} -\frac{7y}{102}

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Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

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Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

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