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Rus_ich [418]
3 years ago
6

This is 6 grade homework please help me

Mathematics
2 answers:
MAXImum [283]3 years ago
4 0

Answer:

what is the problem?

Step-by-step explanation:

yan [13]3 years ago
3 0

Answer:

What work do you need help with tag a photo or write it out.

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Need help with this math problem
grandymaker [24]

Answer:

m<1 = 87

m<2 = 45

m<3 = 45

m<4 = 52

Step-by-step explanation:

if BC intersects <ACD then that means angle 2 and 3 = 90

so that being angle 2 and 3 are the same

now you do 180-(45+48) = 87

now same thing but 180-(45+83) = 52

3 0
3 years ago
Is three quarters of earths water salt water?
aivan3 [116]
The Earth is a watery place. But just how much water exists on, in, and above our planet? About 71 percent of the Earth's surface is water-covered, and the oceans<span> hold about 96.5 percent of all Earth's water. Water also exists in the air as </span>water vapor<span>, in </span>rivers<span> and </span>lakes<span>, in icecaps and </span>glaciers<span>, in the ground as soil moisture and in </span>aquifers<span>, and even in you and your dog.</span>
6 0
2 years ago
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What is the answer to this question 8 1/2- 7 1/4
zysi [14]
1 1/4 because you must make improper fractions
4 0
3 years ago
Read 2 more answers
What is the answer to -4(n+2)+3(n+8)=n-6n
rodikova [14]

Answer:

2.66 or 2 2/3

Step-by-step explanation:

4 0
3 years ago
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Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
3 years ago
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