Answer: The total interest paid on the mortgage is $179550
Step-by-step explanation:
The initial cost of the property is $300000. If he deposits $30000, the remaining amount would be
300000 - 30000 = $270000
Since the remaining amount was compounded, we would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 270000
r = 2% = 2/100 = 0.02
n = 12 because it was compounded 12 times in a year.
t = 25 years
Therefore,
A = 270000(1+0.02/12)^12 × 25
A = 270000(1+0.0017)^300
A = 270000(1.0017)^300
A = $449550
The total interest paid on the mortgage is
449550 - 270000 = $179550
Answer:
A.) 10 years old
Step-by-step explanation:
Sam: John - 14
S = J - 14
S x J = 240
10 = J - 14
0 = J - 14 - 10
-J = -24
J = 24
10 x 24 = 240
Answer:
The answer is 12ac^14/b^3
Answer:
Step-by-step explanation:
Given
Required
The cost of units used
First, calculate the number of units used.
Next, multiply the units used by the cost per units,
Since the cost per unit is not given, we assume that it is x.
So, the total cost is:
The error is that 9 shouldnt be written as nine it should be written as 3x3 or 3^2. So the answer should be 2^3 x 3^2 because 9 can be divided into even more prime factors of 72.
