Answer:
(x+12)(x+5)
Step-by-step explanation:
Formula use: a²+bx+c
- Make one side equal to zero:
Original:
-7x-60 =x² +10x
New:
x² + 17x + 60
New:
(1)x x 60 = 60
- Find factors of 60 that when added, equal to 17.
New:
10 × 6, 60 × 1, 20 × 3, <u>5 × 12</u>, 4 × 15
5 times 12 equal 60, but when added equal to 17.
- Replace the 17 with 5 and 12
New:
x² + 5x + 12x + 60
- Break them off into two equations
New:
x² + 5x l 12x + 60
- Divide each equation into it's simpilest form. Make sure the numbers in the ( ) are the same.
New:
x(x + 5) l +12(x+5)
Let's consider an arbitrary 2x2 matrix as an example,

The columns of

are linearly independent if and only if the column vectors

are linearly independent.
This is the case if the only way we can make a linear combination of

reduce to the zero vector is to multiply the vectors by 0; that is,

only by letting

.
A more concrete example: suppose

Here,

and

. Notice that we can get the zero vector by taking

and

:

so the columns of

are not linearly independent, or linearly dependent.
√23-irrational
104.42-rational
√64-irrational
49.396-rational
10.97846727460-rational
Answer:
27
Step-by-step explanation:
a + b = 7
a - b = 3
2a = 10
a = 5
b = 7 - 5
b = 2
3⁵ / 3² = 3³ using law of indices
3³ = 27.
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