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just olya [345]
3 years ago
13

Tom wishes to purchase a property that has been valued at $300,000. He has $30,000 available as a deposit, and will require a mo

rtgage for the remaining amount. The bank offers him a 25-year mortgage at 2% interest, compounded monthly. Calculate the total interest paid on the mortgage. Round your answer to the nearest dollar.
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0

Answer: The total interest paid on the mortgage is $179550

Step-by-step explanation:

The initial cost of the property is $300000. If he deposits $30000, the remaining amount would be

300000 - 30000 = $270000

Since the remaining amount was compounded, we would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 270000

r = 2% = 2/100 = 0.02

n = 12 because it was compounded 12 times in a year.

t = 25 years

Therefore,

A = 270000(1+0.02/12)^12 × 25

A = 270000(1+0.0017)^300

A = 270000(1.0017)^300

A = $449550

The total interest paid on the mortgage is

449550 - 270000 = $179550

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Find the probability. Leave your answer in simplest fraction form.
kodGreya [7K]

Answer:

5/6

Step-by-step explanation:

The numbers on a six-sided die are as shown:

1, 2, 3, 4, 5, 6

The even numbers are:

2, 4, 6

The numbers greater than 3 are:

3, 4, 5, 6

Both lists together are:

2, 3, 4, 5, 6

Because 5 out of 6 numbers satisfy these conditions, the probability of satisfying these conditions is 5/6.

8 0
2 years ago
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Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)
UkoKoshka [18]

Since the limit becomes the undetermined form

\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}

it means that both polynomials have a root at x=1. So, we can fact both numerator and denominator:

x^3-2x^2+3x-2 = (x-1)(x^2-x+2)

2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)

So, the fraction becomes

\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}

Now, as x approaches 1, you have no problems anymore:

\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}

4 0
3 years ago
I’m really struggling! Please help me!!
Andrew [12]

Answer:

8.0

Step-by-step explanation:

The triangle is a right triangle, so we are able to use trigonometric functions. Relative to the angle of 37°, we have the opposite side which is 6 and the adjacent side which is x. The trig function that uses the opposite and adjacent is tangent(SohCahToa). We can set up the following equation:

tan(37) = \frac{opposite}{adjacent}

tan(37) = \frac{6}{x}

tan(37) evaluates to about , so we can plug it in and solve for x:

0.7536 = \frac{6}{x} \\0.7536x = 6\\x = 7.962

To the nearest tenth, x rounds to 8.0.

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2 years ago
In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

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1 year ago
Which ordered pair (x,y) is a solution to the following?
labwork [276]

Answer:

(-2,1)

Step-by-step explanation:

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