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mote1985 [20]
3 years ago
6

Show that log√7 + log√20 - log√14 = 1/2

Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0

Alright, lets get started.

log \sqrt{7}  + log \sqrt{20}  - log\sqrt{14} = \frac{1}{2}

We could write this square root as \frac{1}{2}

log7^{\frac{1}{2}} + log20^{\frac{1}{2}}- log14^{\frac{1}{2}}

Using the property of logm^{n } = n log (m)

\frac{1}{2}log 7 + \frac{1}{2} log 20 - \frac{1}{2} log14

\frac{1}{2} is common in each term, so

\frac{1}{2}(log7 + log 20 - log 14)

Using property of log m  + log n = log(mn)

\frac{1}{2}(log 140 - log 14)

Using property of log m - log n = log\frac{m}{n}

\frac{1}{2}log\frac{140}{14}

\frac{1}{2} log 10

log 10 value is 1 , hence

\frac{1}{2} * 1 = \frac{1}{2} : Answer

Hope it will help :)

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