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2 years ago

11

Solveequation. a. 5(n – 4) = -60

2 answers:

alexandr402 [8]2 years ago

7 0

Answer:

-8

here's the solution

5(n - 4) = -60

5n - 20 = -60

5n = -60+20

5n = -40

n = -40/5

n= -8

hope it helps

defon2 years ago

4 0

Answer:

n = -8

Step-by-step explanation:

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The slope of the line is 1 because the line moves ror goes up from left to right, making it a positive. The line also moves one block over and one block up.

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How Many Solutions?<br> 3x - 7 = 3(x - 3) + 2<br> No Solution<br> One Solution<br> Infinite Solution

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PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)

trapecia [35]

$\huge \bf༆ Answer ༄$

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:13x + 5y = 670 \: \: \: \: \: (2)$

multiply the equation (2) with 2 [ it won't change the values ]

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y = 1340 \: \: \: \: \: (3)$

Now, deduct equation (1) from equation (3)

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y - 2x - 10y = 1340 - 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:24x = 1080$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 1080 \div 24$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 45$

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(2 \times 45) + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:90 + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 260 - 90$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 170$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 170 \div 10$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 17$

Hence, each van can carry (y) = 17 students in total.

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2 years ago

In the ellipse shown below, the red line segment is called the?

koban [17]

An ellipse uses major axis and minor axis.

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7 0

3 years ago

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B) Mrs. Shakya sold a jewellery at a loss of 5%. If she had sold it at Rs 5,200 more,

Nadusha1986 [10]

Answer:

$\huge{ \fbox{ \sf{Rs \: 40000}}}$

Step-by-step explanation:

$\sf{Let \: CP \: ( \: cost \: price) \: be \: x}$

$\sf{Loss \: \% \: = 5 \% \: }$

$\sf{Selling \: price = CP \: - \: loss \: \% \: of \: CP}$

$\mapsto{ \sf x - \frac{5}{100} \times x}$

$\mapsto{ \sf{x - \frac{x}{20} }}$

$\mapsto{ \sf{ \frac{x \times 20 - x}{20} }}$

$\mapsto{ \sf{ \frac{20x - x}{20}}}$

$\mapsto{ \sf{ \frac{19x}{20}}}$

Now, Finding the New selling price

$\sf{New \: SP \: ( \: selling \: price)} = \frac{19x}{20} + 5200$

$\mapsto{ \sf{ \frac{19x + 5200 \times 20}{20}}}$

$\mapsto{ \sf{ \frac{19x + 10400}{20}}}$

Finally, finding the Cost price :

We have, Profit % = 8 %

$\sf{Cost \: price = Selling \: price \: - \: P\% \: of \: CP}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - 8\% \: of \: x}}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - \frac{8x}{100} }}$

$\mapsto{ \sf{x = \frac{19x + 104000}{20} - \frac{2x}{25} }}$

$\mapsto{ \sf{x = \frac{5(19x + 104000) - 2x \times 4}{100} }}$

$\mapsto{ \sf{x = \frac{95x + 520000 - 8x}{100} }}$

$\mapsto{ \sf{x = \frac{87x + 520000}{100}}}$

$\mapsto{ \sf{100x = 87x + 520000}} \: \: ( \sf{Cross \: multiplication}$

$\mapsto{ \sf{100x - 87x = 520000}}$

$\mapsto{ \sf{13x = 520000}}$

$\mapsto{ \sf{x = \frac{520000}{13}}}$

$\mapsto{ \boxed {\sf{x = 40000}}}$

Therefore, the cost price of the jewellery is Rs 40000

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

5 0

2 years ago