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schepotkina [342]
3 years ago
14

Can any two planes intersect?

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0

Answer:

If two planes intersect, they intersect in a line. Two planes that do not intersect are called parallel. Given a plane and a line, there are three possibilities. The line and the plane intersect in a single point.

Step-by-step explanation:

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Levi is buying office supplies. He can buy 5 packs of paper & 8 staplers for $422 or he can buy 2 packs of paper and 10 stap
sergeinik [125]

Answer:

1 pack of paper = $22

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The attached image will help you!

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4 years ago
Please complete the system of equations.
kogti [31]

Answer:

x=-1,y=0

Step-by-step explanation:

-10y+9x=-9

10y+5x=-5

14x=-14

x=-1

-10y-9=-9

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8 0
3 years ago
Which is an equation in point-slope form for the lines that passes though the points (-1,4) and (3,-4)
Flauer [41]

I don't know if this is the equation you need. But here it is.

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7 0
3 years ago
Ms. Cruz has a tank with 11 fish. After buying two more, she has 2 less than triple the amount of fish Ms. Montesinos has. How m
Katyanochek1 [597]

Answer:

Ms. Montesinos has 5 fish in her tank

Step-by-step explanation:

a) Let y = the amount of fish Ms. Montesinos

b) 3y-2=13

c)

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6 0
3 years ago
Two forces with magnitudes of 150 and 75 pounds act on an object at angles of 30° and 150°, respectively. Find the direction and
kompoz [17]
Answer:

Magnitude: 121.35 pounds

Direction: 21.64°

Explanation:

1) Decompose each force into its x - y components.

2) Force 1, F1: 140 pounds at angle of 30°

x-component: F1,x

F1, x = F1 *cos(30°) = 140 pounds * cos(30°) = 121.24 pounds

y-component: F1,y

F1,y = F1 * sin(30°) = 140 pounds * sin(30°) = 70 pounds.

3) Force 2, F2: 75 poounds at 150°

x-component: F2,x

F2,x = F2 * cos(150°) = 75 pounds * cos(150°) = - 64.95 pounds

y-component: F2,y

F2,y = F2 * sin(150°) = 75 pounds * sin(150°) = 37.5 pounds

4) Resultant Force, Fr

x-component: Fr,x

Fr,x = F1,x + F2,x = 121.24 pounds - 64.95 pounds = 56.29 pounds

y-component: Fr,y

Fr,y = F1,y + F2,y = 70 pounds + 37.5 pounds = 107.5 pounds

4.1) magnitude

|Fr| = √ [ (56.29 pouns)^2 + (107.5 pounds)^2 ] = 121.35 pounds.

4.2) direction

tan(α) = Fr,y / Fr,3 = 56.29 pounds / 107.5 pouns = 0.5236

=> α = arctan(0.5236) = 27.64 °


5 0
3 years ago
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