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3 years ago

Sienna is solving the quadratic equation by completing the square.

2 answers:

7 0

If you would like to know the value of A, you can do this using the following steps:

3x^2 + 9x - 4 = 0
3x^2 + 9x = 4
<span>A(x^2 + 3x) = 4

</span>A = 3:
<span>3 * (x^2 + 3x) = 4
</span>3x^2 + 9x = 4

The correct result would be C: 3.

Ainat [17]3 years ago

3 0

Answer:

the answer is C.) 3

Step-by-step explanation:

i took the test : )

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Can anyone help me with my homework?

Evgesh-ka [11]

I want more points next time....Hehehee!

<em>Solution in attachments!</em>

6 0

2 years ago

Identify the domain and range of the relation:<br> (-5,-3), (-2,1), (1,4), (2,5)

jonny [76]

Domain is the x-coordinate and range is the y - coordinate

$\therefore \: domain = \{ - 5, \: - 2, \: 1, \: 2 \} \\ \\ \&\: range = \{ - 3, \: 1, \: 4, \: 5\}$

3 0

3 years ago

The owner of an apple orchard would like to estimate the mean number of usable apples produced per tree in his

posledela

Step-by-step explanation:

know the normal large sample condition is not met and also there are outliers

7 0

3 years ago

The formula s = StartRoot StartFraction S A Over 6 EndFraction EndRoot gives the length of the side, s, of a cube with a surface

jeyben [28]

Answer:

2.83 inches

Step-by-step explanation:

The formula for surface area of cube = 6s²

Where

s = side length of cube

S.A = 6s²

s² = S.A/6

s = √S.A /6

For cube a

Surface area = 1200 in²

Hence,

side length = √1200/6

Side length = √200

= 14.14 inches

For cube b

Surface area = 768 in²

Hence,

side length = √768/6

Side length = √128

= 11.13 inches

How much longer is the side of a cube with a surface area of 1,200 square inches than a cube with the surface area of 768 square inches?

Therefore,

14.14 inches - 11.13 inches

= 2.83 inches

5 0

2 years ago

Read 2 more answers

7. A number of minor automobile accidents occur at various high-risk intersections in Teton County despite traffic lights. The T

Anit [1.1K]

Answer:

Modification has not reduced the number of accidents.

Step-by-step explanation:

$H_0: \mu\geq0\\H_a:\mu$

A B C D E F G H

Before modification 5 7 6 4 8 9 8 10

After modification 3 7 7 0 4 6 8 2

Difference -2 0 1 -4 -4 -3 0 -8

Mean of differences $M_d = \frac{sum}{8}=\frac{2+0-1+4+4+3-0+8}{8}=2.5$

Standard deviation of differences = $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}=2.9277$

Formula of paired t test :

$t=\frac{M_d}{\frac{s}{\sqrt{n}}}\\t=\frac{2.5}{\frac{2.9277}{\sqrt{8}}}\\t = 2.4152$

Df = n-1 = 8-1 =7

$t critical = t_{(df, \alpha)}=t_{7,0.01}=2.998$

t critical> t calculated

So, We failed to reject null hypothesis

Hence modification has not reduced the number of accidents.

6 0

2 years ago