SOLUTION
From the question, the center of the hyperbola is

a is the distance between the center to vertex, which is -1 or 1, and
c is the distance between the center to foci, which is -2 or 2.
b is given as
![\begin{gathered} b^2=c^2-a^2 \\ b^2=2^2-1^2 \\ b=\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20b%5E2%3Dc%5E2-a%5E2%20%5C%5C%20b%5E2%3D2%5E2-1%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
But equation of a hyperbola is given as

Substituting the values of a, b, h and k, we have
![\begin{gathered} \frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{\sqrt[]{3}^2}=1 \\ \frac{x^2}{1}-\frac{y^2}{3}=1 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%28x-0%29%5E2%7D%7B1%5E2%7D-%5Cfrac%7B%28y-0%29%5E2%7D%7B%5Csqrt%5B%5D%7B3%7D%5E2%7D%3D1%20%5C%5C%20%5Cfrac%7Bx%5E2%7D%7B1%7D-%5Cfrac%7By%5E2%7D%7B3%7D%3D1%20%5Cend%7Bgathered%7D)
Hence the answer is
the equation is Y=-2/3x+2/3
Answer: 13662
Step-by-step explanation: Type into google, 27 times 506
Answer:
Anticlockwise 60°
Step-by-step explanation:
Let my starting point be 0°
Turning to the right(clockwise)40° = 0° + 40° = 40°
I am now at 40° to the right of my starting point.
Turning to the left(anticlockwise) 70° = 40° - 70° = -30°
I am now 30° to the left of my starting point.
Turning to the right 90° = -30° + 90° = 60°
I am 60° to the right of my starting point.
To go back to the startoing point(0°), I should go to the left(anticlockwise) by 60°
This is a change of -60°
-Chetan K