Answer: (a) 0.006
(b) 0.027
Step-by-step explanation:
Given : P(AA) = 0.3 and P(AAA) = 0.70
Let event that a bulb is defective be denoted by D and not defective be D';
Conditional probabilities given are :
P(D/AA) = 0.02 and P(D/AAA) = 0.03
Thus P(D'/AA) = 1 - 0.02 = 0.98
and P(D'/AAA) = 1 - 0.03 = 0.97
(a) P(bulb from AA and defective) = P ( AA and D)
= P(AA) x P(D/AA)
= 0.3 x 0.02 = 0.006
(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)
= P(AA) x P(D/AA) + P(AAA) x P(D/AAA)
= 0.3(0.02) + 0.70(0.03)
= 0.027
Answer:
1.75
Step-by-step explanation:
Low- 81
Q1-82.5
Median- 83.5
Q3-84
High- 85
Answer:
yes they can
Step-by-step explanation:
<u>Answer:</u>
<u>y+1=-2(x-5)</u> - Point Slope Form
<u>y=-2x+9</u> - Slope Intercept Form
<u></u>
Step-by-step explanation:
We will be using point-slope formula, as attached in a picture below.
1) Plug in the slope -2 as "m" in point slope form, along with the two points, (5, -1)
<u>y+1=-2(x-5)</u>
2) Next, if you want to put the line into slope-intercept form, you will need to distribute -2 to x and -5:
y+1=-2x+10
3) Now, subtract 1 from both sides:
<u>y=-2x+9</u>