The same line! hope this helps! i’m not 100% sure so if i’m wrong don’t flame me
No. 43 is a prime number. It has no other factors besides ' 1 ' and itself.
Answer:
The probability will be 0.3085 or 0
Step-by-step explanation:
Given:
True mean=12.5
Sample mean =12.6
Standard deviation=0.2
Samples=100
To Find:
Probability that exceeds 12.6 ounces.
Solution:
Calculate the Z-score for given means and standard deviation.
So
Z-score= (true mean -sample mean)/standard deviation.
Z-score=(12.5 -12.6)/0.2
=-0.1/0.2
=-0.5
Now Using Z-table
P(X≥-0.5)=p(Z≥-0.5)=0.3085
Hence Probability that sample mean weight exceeds will be 0.3085
OR
By using Normal distribution with sampling ,it will be as follows
Z=(X-u)/[Standard deviation/Sqrt(No of samples)]
Z=(12.6-12.5)/(0.2/Sqrt(100)
Z=0.1/0.2/10
Z=5
So P(X≥12.6 )=P(Z≥5)=1
Pr(Z≥5)=1-1=0.
(Refer the attachment )
Hence Probability of getting ounces greater than 12.6 is '0'.
The sampling is of 0.02 size hence graphically it looks likely.
as shown in attachment.
The required probability for
a. 0.2058
b. 0.98
c.0.016
<h3>
What is probability?</h3>
Probability can be defined as the ration of favorable outcomes to the total number of events.
Let use binomial distribution.
Probability answering a question correctly=1/3 =0.33
Probability of not answering a question correctly
=1–1/3
=2/3
a) Out of 10 probability of answering 4 correctly
=10c4 x (0.33)^4 x (0.66)^6
Upon simplification, 0.2058
b) Find the probability for getting at least 2 correct answers
= 1 - { 10c8 x (0.33)^8 x (0.66)^2+ 10c9 x (0.33)^9 x (0.66)^1 + (0.33)^10}
= 0.98
c).Find the probability for getting 2 or 3 incorrect answers.
10c8 x (0.33)^8 x (0.66)^2 + 10c7 x (0.33)^7 X (0.66)^3
=0.002 + 0.014
= 0.016
Thus the required probabilities are: 0.2058, 0.98 , 0.016
Learn more about probability here:
brainly.com/question/14290572
#SPJ1
Answer:
42-x = James' money now
Step-by-step explanation: