Question

One x-intercept of the graph of the of the cubic function f(x) = x^3 – 2x^2 – 111x – 108 is –9.

Answer 1

Answer:

The zeros of the given function are -9,-1 and 12.

Step-by-step explanation:

The given function is

$f(x)=x^3-2x^2-111x-108$

It is given that the x-intercept of the graph is -9, therefore -9 is a zero of the function.

Since -9 is the zero of the function, therefore (x+9) is a factor of f(x). Use synthetics method or long division method to divide the function by (x+9).

$f(x)=(x+9)(x^2-11x-12)=0$

$f(x)=(x+9)(x^2-12x+x-12)=0$

$f(x)=(x+9)(x(x-12)+(x-12))=0$

$f(x)=(x+9)(x-12)(x+1)=0$

Use zero product property and quote each factor equal to 0.

$x=-9,-1,12$

Therefore zeros of the given function are -9,-1 and 12.