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lidiya [134]
4 years ago
15

How to find a line that passes through two points?

Mathematics
1 answer:
Pepsi [2]4 years ago
4 0
You can find a line that passes through two points by using the slope formula and the two points the line passes through

Slope Formula =\frac{y2-y1}{x2-x1}
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What is the fractional equivalent of 225%?
vitfil [10]
You would start out by putting 225 over 100 then simplifying from there. You would end up getting 9/4. As a mixed number that would be 2 and 1/4.
7 0
3 years ago
Read 2 more answers
Can a few people pls tell me the right answer pls and thank you
sergey [27]
D is the right answers
hope it help... :)
4 0
3 years ago
Two angels re supplementary. The larger angle is 48 degrees more than the 10 times the smaller angle. Find the measure of each a
evablogger [386]
Supplementary angles are two angles that add up to 180°.

STEP 1:
find the value of x

x= smaller angle
10x + 48= larger angle

Add the two angles above to equal 180.

x + (10x + 48)= 180
combine like terms

11x + 48= 180
subtract 48 from both sides

11x= 132
divide both sides by 11

x= 12° smaller angle


STEP 2:
find the value of the second angle

=10x + 48
=10(12) + 48
=120 + 48
=168° larger angle


CHECK:
12° + 168°= 180°
180°= 180°


ANSWER: The smaller angle is 12° and the larger angle is 168°.

Hope this helps! :)
8 0
3 years ago
Name Date 34bral Kuta Software - Infinite Algebra 2 Solving Absolute Value Equations Solve each equation. 1) 13x1=9 2) 1-3r1=9 R
vichka [17]
-5|3+4k|=-115

start by dividing both sided by -5

\frac{-5}{-5}|3+4k|=-\frac{115}{-5}|3+4k|=23

when we have an absolute we obtain two equations, one for the positive value and one for the negative value

\begin{gathered} 3+4k=23 \\ -(3+4k)=23 \end{gathered}

solve each of them

\begin{gathered} 3+4k=23 \\ 4k=23-3 \\ 4k=20 \\ k=\frac{20}{4}=5 \end{gathered}

for the second equation

\begin{gathered} -(3+4k)=23 \\ -3-4k=23 \\ -4k=23+3 \\ -4k=26 \\ k=-\frac{26}{4}=-6.5 \end{gathered}

the solutions for k are -6.5 and 5

4 0
1 year ago
Write the coordinates of the vertices after a reflection across the line y = 4
Lubov Fominskaja [6]
A'(-9,4)
B'(-4,4)
C'(0,-4)
D'(-5,-4)
8 0
3 years ago
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