Answer: 18x^3-9x^2+21x
Solution:
3x(6x^2-3x+7)=
Applying the distributive property in the multiplication to eliminate the parentheses:
(3x)(6x^2)+(3x)(-3x)+(3x)(7)=
(3*6)x^(1+2)+3*(-3)x^(1+1)+(3*7)x=
18x^3-9x^2+21x
<span>{[(16 ÷ 4) × (2 × 6)] ÷ 6} + 4 =
</span><span>{[(4) × (12)] ÷ 6} + 4 =
</span>{[4 × 12] ÷ 6} + 4 =
{[48] ÷ 6} + 4 =
{48 ÷ 6} + 4 =
{8} + 4 =
8 + 4 =
12
Answer:
$11.25
Step-by-step explanation:
1.25 × 9 = 11.25
