It should be $109 for the bike because if u divide 327 by 3 it equals 109.
1.
a) metres to centimetres :
multiply length by 100
b) metres to millimetres:
multiply length by 1000
c) kilograms to grams:
multiply the mass value by 1000
d) litres to millilitres :
multiply volume by 1000
2.
a) 3 m = 3× 100 = 300 cm
b) 28 cm = 28 × 10 = 280 mm
c) 2.4 km = 2.4 × 1000
= 24 × 10^-1 × 10^3
= 24 × 10^2 =2400 m
d) 485 mm =485 / 10
= 485 / 10 ^1
= 485 × 10 ^-1
= 48.5 cm
e) 35 cm = 35 / 100
= 35 /10^2
= 35 × 10 ^ -2
= 0.35 m
f) 2.4 m = 2.4 / 1000
= 24 × 10 ^-1 / 10^3
= 24 × 10^-1 × 10 ^-3
= 24 × 10 ^ -4
= 0.0024 km
g) 2495 mm = 2495 /1000
= 2495 /10^ 3
= 2495 × 10 ^-3
=2.495 m
First you would need to find out how many 9 payments of 58$ would be and that is 522. Then you would need to subtract the 522 and the 480 and your answer would be 42$ so the interest would be 42$
Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
2 11/12 is your answer because
3-2=1+1=2
and 4/12 - 3/12 = 1/12 + 10/12 = 11/12.
