Answer:
x=133 y=-25
Step-by-step explanation:
I'll do both ways for you. So let's start with Substitution:
With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.
x + 2y = 83 & x + 5y = 8
Solve for x.
x = 83 - 2y & x = 8 - 5y
Once you have solved for x, set each equation equal to one another and solve for y now.
83 - 2y = 8 - 5y
Isolate all variables to one side:
83 = 8 - 3y
Now subtract the 8 to fully isolate the y variable:
75 = -3y
Divide by -3:
-25 = y Now that you have your first variable, plug it into one of the original equations and solve for x.
x + 2(-25) = 83
x - 50 = 83
x = 133
Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:
Put each equation on top of one another and subtract:
x + 2y = 83
- (x + 5y = 8)
The x's will cancel out:
(x - x) + (2y - 5y) = (83 - 8)
Simplify:
-3y = 75
Solve for y
y = -25
Then, plug y = -25 into one of the original equations:
x + 5(-25) = 8
Solve for x:
x - 125 = 8
x = 133
Hope this helps!
Um, we see that the slice created the triangle, and the formula to find the area of the triangle:
1/2×B×h where B represent Base and h represent height.
In this case, Base=5 cm
Height=11 cm
A=1/2×11×5
A=5.5×5
A=27.5 square cm. As a result, the area of the resulting two-dimensional cross section is 27.5 square cm. Hope it help!
Answer:
bro you didnt put no picture up
Step-by-step explanation:
Answer:
Hello, mizuki here to help!
The correct answer would be C
Step-by-step explanation:
Ok, so the total of homework he got was 50, and the number of homework he got in monday was 16.
So.... it should be expressed as 16/50 which would be 0.32
13/52= 1/4 or .25
If you have a scientific calculator it really helps with simplifying numbers to the lowest term.