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2 years ago

What is the probability of tossing a coin three times and getting tails each time?

Mathematics

1 answer:

telo118 [61]2 years ago

3 0

Answer:

1/8

Step-by-step explanation:

This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.

The probability of flipping tails is 1/2. We need three of these.

1/2 x 1/2 x 1/2 = 1/8

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Enter an expression for the perimeter of the given figure. Simplify the expression.

dlinn [17]

Answer:

4x + 28.4 in.

Step-by-step explanation:

perimeter = sum of lengths of sides

perimeter = x + 2 + x + 2 + x + 2 + x + 2 + 10.2 + 10.2

perimeter = 4x + 28.4

3 0

2 years ago

Find the probability for choosing a letter at random from the word: Probability P(not P) A.) 1/11 B.) 2/11 C.) 5/11 D.) 10/11

elixir [45]

Answer:

D.) 10/11

Step-by-step explanation:

Here the given word Probability has 11 letters in it. And we have to calculate the Probability of not selecting a letter P from the above word.

So the formula for calculating any probability is Total Favorable outcomes / Total number of outcomes.

Here total number of outcomes are 11 as word Probability has 11 letters.

So the probability of selecting letter P from word Probability = $\frac{1}{11}$

Now the P(not P) = 1 - P(selecting letter P)

= 1 - $\frac{1}{11}$ = $\frac{10}{11}$

6 0

2 years ago

How do i find answes to endjunity geomatry

konstantin123 [22]

Answer:

Hey there !

Under the More button, select View Course Structure.

Find the lesson to view the assessment answers. Click Quiz Answers.

All the assessment questions related to the lesson are found in the pop-up window. To view a question and answer, select a question number.

5 0

3 years ago

In the expression (x^2 + 3), the base is ?

azamat

Answer to your question
The base is X
What are the other stuff then?
2 is the power
3 is the constant

8 0

2 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

2 years ago

Read 2 more answers