Answer:
Yes, the geometric distribution is appropriate.
Step-by-step explanation:
sorry if im wrong
Answer:
2.5e-0.04x = 1.2 + 0.2x
Step-by-step explanation:
Given that:
Insect A:
Initial population, Po = 2.5 million
Rate of decline = 4%
Insect B:
Initial Population (Po) = 1.2 million
Yearly increase = 200,000 = (200,000/1,000,000) = 0.2
For insect A:
P(t) = Po(1 - r)^t = Po*e^-rt
Po*e^-rt = 2.5e^-0.04t ----(1)
For Insect B:
P(t) = Po + (yearly increase) * t
P(t) = 1.2 + 0.2t - - - - - (2)
Equating (1) and (2)
2.5e^-0.04t = 1.2 + 0.2t
It might be helpful to write up the question like this:
300=100%
3=1%
120=
If you do this, you’ll see that the question is really easily solved by just finding the number necessary to multiply 3 with to get 120.
If you understand this, the rest should follow.
1/2x+20=1/3x+30
Subtract 20 on both sides
1/2x=1/3x+10
Subtract 1/3x on both sides
1/6x=10
Multiply by 6 on both sides
X=60
Answer:

Find the midsegment of the triangle which is parallel to CA.

Tip
- A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle.
- This segment has two special properties. It is always parallel to the third side, and the length of the midsegment is half the length of the third side.
- If two segments are congruent, then they have the same length or measure.In other words, congruent sides of a triangle have the same length.

We have to find the segment which is parallel to CA.
From the given data,
The segment EG is the midsegment of the triangle
ABC.
So we have,
A midsegment of a triangle is a segment connecting the midpoints of two sides of a triangle. This segment has two special properties. It is always parallel to the third side.

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