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Law Incorporation [45]
3 years ago
13

Prove that sinΘcosΘ=cotΘ is not a trigonometric identity by producing a counterexample.

Mathematics
1 answer:
yan [13]3 years ago
4 0
<span>sin x + cos x = l would be the answer</span>
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How do I solve 10p+5=18p-6/2
mihalych1998 [28]
<span>10p+5=18p-6/2 
10p + 5 = 18p -3 
10p - 18 p = -3 -5
-8p = -8
p = -8/-8
p =1</span>
3 0
3 years ago
What’s (3b-5c)(2x+5y) squared
lukranit [14]
Answer: In your problem, you said that they are squared. However, it is not written as squared. We just have to multiply them.

We can use the FOIL method.

(3b - 5c)(3x + 5y)

6bx + 15by - 10cx - 25cy

There are no like terms, so that expression is our final answer.
8 0
3 years ago
What number goes into 88 and 60 both
almond37 [142]
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Given f(x)=4x^2-9 and g(x)=2x+3 find each function or value<br> (f-g)(4)
yulyashka [42]
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4 0
3 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
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