Answer:
<u>The perimeter of the square is option E. 16√5 mm.</u>
<u>The area of the square is option A. 80 mm².</u>
Step-by-step explanation:
1. Let's calculate the perimeter of this square:
The perimeter of a square is the sum of its side 4 times, thus:
Perimeter = 4√5 + 4√5 + 4√5 + 4√5
<u>Perimeter = 16 √5</u>
<u>Perimeter = 4 * 4√5 = 16√5</u>
<u>The correct answer is option E. 16√5 mm</u>
2. Let's calculate the area of this square:
The area of a square is the length of its side squared, thus:
Area = (4√5)²
Area = 4√5 * 4√5
Area = (4 * 4 * √5 * √5)
Area = 16 * 5 = 80
<u>The correct answer is A. 80 mm²</u>
. a. answers vary
b. Yes; the taller the person is, the longer his or her reach.
c. The independent quantities were represented by the x-axis, while the dependent
_quantities were represented using the y-axis.
d. A trend line can generalize the trend in the data.
1-18. a. The graph is in the first quadrant because negative lengths do not exist; the range
of the data determines the kind of graph.
b. Counting by 10’s makes the graph a reasonable size.
c. In this situation, including the origin with the graph is not suggested. It is easier to
see the trend line when the data are not bunched together, and this can be done by
changing the range of the graph to exclude the origin.
d. The graph should include the maximum height (that of Yao Ming) on the x-axis
and the height of the tunnel on the y-axis.
1-21. a. b. c. d.
e. f. g. h.
1-22. a. –8 b. 29 c
The answer is 20 because if you subtract the two Q which is 40 and 20 that is your interquartile range
