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SSSSS [86.1K]
3 years ago
6

In a hypothesis test, the claim is μ≤25 while the sample of 34 has a mean of 21 and a population standard deviation of 5.9 from

a normally distributed data set. In this hypothesis test, would a z test statistic be used or a t test statistic and why?
Mathematics
1 answer:
iogann1982 [59]3 years ago
5 0

Answer:

z test statistic

Step-by-step explanation:

Given : In a hypothesis test, the claim is μ ≤ 25 while the sample of 34 has a mean of 21 and a population standard deviation of 5.9 from a normally distributed data set.

To Find : In this hypothesis test, would a z test statistic be used or a t test statistic and why?

Solution:

Claim : μ ≤ 25

Sample size = n = 34

Population Standard Deviation = 5.9

Since n > 30 and we are given the standard deviation of population .

So, we will use z test statistics .

Hence  In this hypothesis test,  z test statistic would be used.

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Write 5600 in standard form
Mrac [35]

Answer:

5.6 x 10^3 (10 to the power of 3)

i.e. 5600 = 5.6 x 10^3 because you have to go back 3 times to get 5.6 *you cannot have a number less than 1 or more than 10*

So the power of 3 is the amount of times you had to move back

Step-by-step explanation:

This is how you write 5600 in standard form!

HOPE THIS HELPS!!

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3 years ago
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Find the value of x that satisfies the equation 24=17-14x
Anna35 [415]

Answer:

x= -0.5

Step-by-step explanation:

6 0
3 years ago
Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = 3 (*sqaure root sign*) t (20 − t), [0,
mafiozo [28]

9514 1404 393

Answer:

  • maximum: 15∛5 ≈ 25.6496392002
  • minimum: 0

Step-by-step explanation:

The minimum will be found at the ends of the interval, where f(t) = 0.

The maximum is found in the middle of the interval, where f'(t) = 0.

  f(t)=\sqrt[3]{t}(20-t)\\\\f'(t)=\dfrac{20-t}{3\sqrt[3]{t^2}}-\sqrt[3]{t}=\sqrt[3]{t}\left(\dfrac{4(5-t)}{3t}\right)

This derivative is zero when the numerator is zero, at t=5. The function is a maximum at that point. The value there is ...

  f(5) = (∛5)(20-5) = 15∛5

The absolute maximum on the interval is 15∛5 at t=5.

5 0
2 years ago
If you bought something for $372.60 including an 8% tax, what was the price before the tax?
Dvinal [7]

Answer:

  • $345

Step-by-step explanation:

<u>Let the price before tax be x, then we have:</u>

  • x + 8% = 372.60
  • x + 0.08x = 372.60
  • 1.08x = 372.60
  • x = 372.60 / 1.08
  • x = 345

The initial price was $345

7 0
2 years ago
CORRECT ANSWER GETS BRAINLIEST
borishaifa [10]
6 (-9)-3/2=14
-108/2-3/2=14
-111/2 = 14
false

12+2=14
14=14

B
7 0
3 years ago
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