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lawyer [7]
4 years ago
10

Which of these ordered triples indicates where the plane cuts the x-axis for this equation? 3x + 4y + 6z = 12

Mathematics
1 answer:
Eduardwww [97]4 years ago
8 0

Answer:

Option A is correct.

Step-by-step explanation:

Given equation is 3x + 4y + 6z = 12

We have to find ordered triplet which indicate where the plane cuts the x-axis.

To find x-coordinate where plane cuts the x-axis we put y and z equal to 0.

3x + 4 × 0 + 6 × 0 = 12

3x + 0 + 0 = 12

3x = 12

x = 4

So, the coordinate where  it cuts x-axis is ( 4 , 0 , 0 )

Therefore, Option A is correct.

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Given this table of values, what is the value of f(-4.5) ? <br><br> help pelase !!
True [87]

Answer:

12.6

Step-by-step explanation:

f(-4.5) means "what is the y-value when x equals -4.5?"

We see that when x = -4.5, our y or f(x) value is 12.6

7 0
3 years ago
Find the simple interest paid to the nearest cent for each loan, interest rate, and time. $500, 12%, 18 months
iris [78.8K]

Answer: The interest is $60


Step-by-step explanation:

500*112%=$560

560/18=$31.11

$60 in interest is paid, or an additional $3.33 a month (Bringing the monthly loan payment to a grand total of $31.11)

4 0
3 years ago
Read 2 more answers
What is the number 5 2/7 written as a improper fraction
WARRIOR [948]

Answer:

the answer is 37/7

Step-by-step explanation:

u multiply the 5 and the seven and add the 2 and u get 37/7 so u keep the denominator the same

5 0
3 years ago
Amanda bought 19 packs of cookies for $22.99 from the supermarket. How many packs of cookies can she buy for $59.29?
lbvjy [14]

Answer:

49

Step-by-step explanation:

1.21 x 49 = 59.29

5 0
3 years ago
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
3 years ago
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