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iogann1982 [59]
3 years ago
8

The perimeter of a triangle is 64cm ,the sides are the ratio 6:5:5 , work out the area of the triangle

Mathematics
1 answer:
Fofino [41]3 years ago
4 0
The area is 192 cm^2

the sides are 20 20 24 with the base being 24

to figure out the height you have to use Pythagorean theorem of the triangle cut in half so 12^2 + b^2 = 20^2
b= 16 = height

b*h* .5= area 16* 24* .5= 192
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Three times a number t minus twelve equals forty
tekilochka [14]
3 · t - 12 = 40

3t - 12 = 40    |add 12 to both sides

3t = 52    |divide both sides by 3

t = 52/3

t = 17 1/3
5 0
3 years ago
tanji creates a "square, circle" repeating pattern. Kenji creates a "Square, circle, trianglr, cricle" repeating pattern. if bot
RoseWind [281]

Both tanji & kenji have same number of circles i.e. 50 .

<u>Step-by-step explanation:</u>

Here we have , tanji creates a "square, circle" repeating pattern. Kenji creates a "Square, circle, triangle, circle" repeating pattern. if both tanji and kenji have 100 shapes in their patterns,  . We need to find that which pattern contains more circles .Let's find out :

<u>tanji creates a "square, circle" </u>

it's given that tanji has 100 shapes and he is repeating this pattern . In this pattern circle comes 1 every time out of 2 shapes :

Total number of times circle = \frac{100}{2}(1)

Total number of times circle = 50

<u>Kenji creates a "Square, circle, triangle, circle" </u>

it's given that tanji has 100 shapes and he is repeating this pattern . In this pattern circle comes 2 every time out of 4 shapes :

Total number of times circle = \frac{100}{4}(2)

Total number of times circle = 50

Both tanji & kenji have same number of circles i.e. 50 .

3 0
3 years ago
Find four consecutive numbers whose sum equals 218
Softa [21]

Answer: 53, 54, 55, and 56

Step-by-step explanation: This problem states that the sum of 4 consecutive numbers is 218 and it asks us to find the numbers.

4 consecutive numbers can be represented as followed.

X ⇒ <em>first number</em>

X + 1 ⇒ <em>second number</em>

X + 2 ⇒ <em>third number</em>

X + 3 ⇒ <em>fourth number</em>

Since the sum of our 4 consecutive numbers is 218, we can set up an equation to represent this.

X + X + 1 + X + 2 + X + 3 = 218

On the left side of the equation, we can combine our x's and our numbers.

4x + 6 = 218

      -6     -6   ← <em><u>subtract 6 from both sides of the equation</u></em>

4x = 212

÷4    ÷4   ← <u><em>divide both sides of the equation by 4</em></u>

 <u>X = 53</u>

<u />

X ⇒ <em>first number   = 53</em>

X + 1 ⇒ <em>second number   = 54</em>

X + 2 ⇒ <em>third number   = 55</em>

X + 3 ⇒ <em>fourth number   = 56</em>

<em />

<em>Therefore, our 4 consecutive numbers are </em><em>53</em><em>, </em><em>54</em><em>, </em><em>55</em><em>, and </em><em>56</em><em>.</em>

4 0
3 years ago
Select the correct answer.
Pani-rosa [81]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Find the volume of this square based pyramid. 5 cm 5 cm 5 cm. Round to the nearest tenth.
vodka [1.7K]

Answer:

41.666 cm³ or 41.7 cm³  rounded to the nearest tenth.

Step-by-step explanation:

Volume of a square pyramid = base length² × height ÷ 3

25 × 5/3 = 41. 666

Have a great day:)

4 0
3 years ago
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