Question

On the coordinate plane below, Point P is located at (2,-3), and point Q is located at (-4,4).

Answer 1

Answer:

Approximately 9 units.

Step-by-step explanation:

To find the distance between two ordered pairs, we can use the distance formula. The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let (2,-3) be x₁ and y₁ respectively, and let (-4,4) be x₂ and y₂, respectively.

$d=\sqrt{(-4-2)^2+(4--3)^2} \\d=\sqrt{(-6)^2+(7)^2} \\d=\sqrt{36+49} \\d=\sqrt{85}\approx9$