Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
Answer:
9 units
Center is at (5, 0)
Step-by-step explanation:
The radius of the circle is equal to the square root of 81
= ±9
Since the radius of a circle must be positive the answer is 9 units.
The center of the circle is at (5, 0)
#6 (you should download an app call “Photomath “)
3/4 + 1/8
you gotta find a common denominator
so you end up with
(24+4)/32
=28/32
7/8 is now complete