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3 years ago

Solve the following inequality: –1 + 6(–1 – 3x) > –39 – 2x.

Mathematics

2 answers:

insens350 [35]3 years ago

7 0

–1 + 6(–1 – 3x) > –39 – 2x.
-1-6-18x>-39-2x
-7-18x>-39-2x
-18x>-32-2x
-16x>-32
x<2

B. x<2

lorasvet [3.4K]3 years ago

6 0

Answer:

X<2

Step-by-step explanation:

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Helpp! subtract 8/9-1/3

Archy [21]

Answer:

=5/9 or 0.5

Step-by-step explanation:

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4 years ago

Read 2 more answers

Find the equation of the axis of symmetry of the following parabola algebraically.

mr Goodwill [35]

Answer:

the equation of the axis of symmetry is $x=8$

Step-by-step explanation:

Recall that the equation of the axis of symmetry for a parabola with vertical branches like this one, is an equation of a vertical line that passes through the very vertex of the parabola and divides it into its two symmetric branches. Such vertical line would have therefore an expression of the form: $x=constant$ , being that constant the very x-coordinate of the vertex.

So we use for that the fact that the x position of the vertex of a parabola of the general form: $y=ax^2+bx+c$ , is given by:

$x_{vertex}=\frac{-b}{2\,a}$

which in our case becomes:

$x_{vertex}=\frac{-b}{2\,a} \\x_{vertex}=\frac{48}{2\,(3)} \\x_{vertex}=\frac{48}{6} \\x_{vertex}=8$

Then, the equation of the axis of symmetry for this parabola is:

$x=8$

4 0

4 years ago

the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a

Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, ( $\mathbf{4\sqrt 3}$ )

The exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

The given parameters are:

$\mathbf{Area =56\pi\sqrt 6}$

$\mathbf{r=4\sqrt 3}$

The surface area of a cylinder is calculated as:

$\mathbf{Area = 2\pi rh + 2\pi r^2}$

Substitute values for Area

$\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}$

Divide through by pi

$\mathbf{56\sqrt 6= 2 rh + 2r^2}$

Substitute value for r

$\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}$

Collect like terms

$\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}$

Make h the subject

$\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}$

$\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}$

Rationalize

$\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}$

$\mathbf{h = 7\sqrt 2- 4\sqrt 3}$

Hence, the exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

Read more about surface areas t:

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2 years ago

1. What is the value of 668 + 575 + 453, rounded to

Brums [2.3K]

Answer:

E. 1,700 is your answer.

Step-by-step explanation:

What you do is you add 668 + 575 + 453 together.

668 + 575 + 453 = 1,696.

The hundreds place is the 9. Since the 9 is bigger than 4 it gets rounded up. That means the 6 in front of the 9 becomes a 7 and 9 and 6 become a zero.

E. 1,700 is your answer.

6 0

3 years ago

During a football game a concession stand sold a family three hamburgers and two hotdogs for a total of $13 it's sold another fa

guajiro [1.7K]

Answer:

The price of each hamburger is $3

The price of each hot dogs is $2 .

Step-by-step explanation:

Given as :

The total price of 3 hamburger and 2 hot dogs = $13

The total price of 2 hamburger and 5 hot dogs = $16

Let The price of each hamburger = $x

Let The price of each hot dogs = $y

Now, According to question

3 x + 2 y = 13 .........A

2 x + 5 y = 16 .......B

Now, Solving to eq A and B

3 × (2 x + 5 y ) - 2 × (3 x + 2 y ) = 3 × 16 - 2 × 13

Or, (6 x + 15 y) - (6 x + 4 y) = 48 - 26

Or, (6 x - 6 x) + (15 y - 4 y) = 22

Or, 0 + 11 y = 22

∴ y = $\dfrac{22}{11}$

i.e y = $2

so, The price of each hot dogs = y = $2

Now, Put the value of y into eq B

i.e 2 x + 5 y = 16

or, 2 x + 5 × 2 = 16

or, 2 x = 16 - 10

or, 2 x = 6

∴ x = $\dfrac{6}{2}$

i.e x = $3

So, The price of each hamburger = x = $3

Hence, The price of each hamburger is $3 and The price of each hot dogs is $2 . Answer

3 0

4 years ago