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3 years ago

Which expression is equivalent to 64y18 – 1000z6?

Mathematics

2 answers:

spin [16.1K]3 years ago

5 0

Answer:

$(4y^6)^3-(10z^2)^3$

Step-by-step explanation:

We have to find which expression is equivalent to

$64y^{18}-1000z^6$

This can also be written as:

$4^3(y^6)^3-10^3(z^2)^3\\\\=(4y^6)^3-(10z^2)^3$

Hence, option first is correct

natta225 [31]3 years ago

3 0

Answer:

$(4y^{6})^{3}-(10z^{2})^{3}$

Step-by-step explanation:

we have

$64y^{18}-1000z^{6}$

we know that

$64=4^{3}$

$y^{18}=(y^{6})^{3}$

$1000=10^{3}$

$z^{6}=(z^{2})^{3}$

Substitute the values in the expression

$(4^{3})((y^{6})^{3})-(10^{3})((z^{2})^{3})$

$(4y^{6})^{3}-(10z^{2})^{3}$

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Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

The following triangles are similar. True or False.

monitta

Answer:

It would be true

4 0

2 years ago

3(4*5)=(3*4)5 what is thsi

Serggg [28]

This is the associative property. Basically if you move the parenthesis either to left or right you’ll still get the right answer. So 4 times 5 equals 20 and 20 times 3 equals 60. 3 x 4 equals 12 and 12 x 5 equals 60

8 0

3 years ago

Read 2 more answers

In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66.What

Lunna [17]

Answer:

We conclude that the lower limit of a box-and-whiskers display is 65.

We conclude that the upper limit of a box-and-whiskers display is 77.

Step-by-step explanation:

Definition: A box-and-whisker plot or boxplot is a diagram based on the five-number summarytext annotation indicator of a data set.

In a statistics class, 10 scores were randomly selected with the following results: 74, 73, 77, 77, 71, 68, 65, 77, 67, 66.

We conclude that the lower limit of a box-and-whiskers display is 65.

We conclude that the upper limit of a box-and-whiskers display is 77.

3 0

3 years ago

HELPPPPPPPPPPP

liubo4ka [24]

(A) Find the approximate length of the plank. Round to the nearest tenth of a foot.
Given that the distance of the ground is 3ft.
In order to get the length of the plank,
we can use the this one.

cos 49 = ground / plank
cos 49 = 3 / plank
plank = cos 49 / 3
plank = 0.10 ft

(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.

The remaining angle is equal to
angle = 180 - (90+49)
angle = 41

Finding the height.
tan 41 = height / ground
tan 41 = height / 3
height = tan 41 / 3
height = 0.05 ft.

(A) 0.10 feet
(B) 0.05 feet

3 0

3 years ago