Answer:
<h3>
The reason which is incorrect is in Step 2 and reason 2</h3>
Step-by-step explanation:
Given that Logan's equation is 
<h3>To simplify and find the which reason is incorrect :</h3>
Logan's solution and reasoning for solving an equation are shown below:
Step1 
Reason 1: Given
Step2 
Reason 2: Addition Property of Equality
Step3 
Reason 3: Simplify
Step4 
Reason 4: Division Property of Equality
Step5 
Reason 5: Simplify
<h3>
The reason which is incorrect is in Step 2 and reason 2</h3><h3>
The corrected steps are</h3>
Step1 
Reason 1: Given
Step2 
Reason 2: Distributive property
Step3 
Reason 3: Simplify
Step4 
Reason 4: Addition Property of Equality
Step5 
Reason 5: Simplify
Step6 
Reason 6: Division Property of Equality
Step7 
Reason 7: Simplify
<h3 />
1 is 0.958 and 2 is 0.947
Answer:
-13
Step-by-step explanation:
since x is positive, |x+8| becomes x+8. since x>5, 5-x is negative so |5-x| becomes x-5 (-(5-x)=-5+x=x-5). so now we have x-5-(x+8)=x-5-x-8=-5-8=-13
Area of triangle = 1/2 base x height
15.588 = 1/2 * base x 5.196
15.588 = base x 2.598
base = 15.588 / 2.598 = 6
equi center of triangle = 1/3*5.196 = 1.732
radius of circle = Sqrt(1.732^2 + 3^2) =
sqrt (2.999824 +9) =
sqrt(11.999824) = 3.464
rounded to nearest tenth = 3.5 inches
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750
Correct answer is C)</span>