The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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Answer:
x = 0 and x = 3
Step-by-step explanation:
I will assume that you mean:
4 8
---- + --------- = 4
x x + 2
Here the LCD is x(x + 2).
Multiplying all 3 terms by x(x + 2), we get:
4(x + 2) + 8x = 4(x)(x + 2), or
4x + 8 + 8x = 4x^2 + 8x
Cancelling the 8x terms, we have:
12x = 4x^2, or 3x = x^2, or x^2 - 3x = 0.
Factoring, we get x(x - 3) = 0, which results in x = 0 and x = 3.
No
X would have to equal 6 or greater as if x was 5
5+3 is the same as 8
X² = 16
x = ±√16
x = <span>±4
</span>The roots of this equation are -4 and 4
<span>Сorrect answer is third from above</span>
First I chose two points on the line that fall on 2 intervals or 2 lines. Then if found the slope of the two points. Using the slope and one of the points I pugged the numbers into an equation to solve for b. Once I found b I wrote an equation using b and the slope.
y=-2/3+300
steps:
(250,200)(300,100)
100-200/300-150
-100/150 or -2/3
100=-2/3(300)+b
100=-200+b
300=b
y=-2/3b+300
