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s2008m [1.1K]
3 years ago
5

a rectangle has an area of 18cm2. the lengths of the sides are whole numbers. how long can the sides be? give all the examples y

ou can think of because i cannot
Mathematics
1 answer:
Kisachek [45]3 years ago
3 0
3&6 9&2 1&18 sides combination are possible!
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a study examined the effectiveness of an ear molding technique used to correct ear deformities in newborns without the need for
inna [77]

Answer:

The sample proportion of successful procedures is 0.962.

Step-by-step explanation:

The sample proportion of successful procedures is the number of successfiç procedures divided by the total number of procedures.

In this problem:

158 procedures, of which 152 were successful. So

p = 152/158 = 0.962

The sample proportion of successful procedures is 0.962.

4 0
3 years ago
6 customers entered a store over the course of 18 minutes. At what rate were the customers entering the store in customers per m
alexandr1967 [171]

Answer:

3 minutes

Step-by-step explanation:

18 divided by 6 = 3 minutes

Hope this helps :)

7 0
3 years ago
If there are 2.2 pounds in 1 kilogram how many pounds are there in x kilograms?
nirvana33 [79]

Answer:

P=x/2.2

Step-by-step explanation:

We can create an equation to solve this.

Let the number of pounds be P

Let the number of kilograms be X

Now, we know that for 1 kilogram, there is 2.2 pounds.

Therefore if we have 1 kilogram (X) then we will have 2.2 pounds (P).

<u>X=2.2P</u>

All you have to do now is rearrange the equation to find the number of pounds in x kilograms. To do this divide both sides by 2.

Therefore you will get P=x/2.2

5 0
3 years ago
What is the value of x? Show your work.
erma4kov [3.2K]
Well they are similar by ASA 
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28=4x
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5 0
3 years ago
Read 2 more answers
A scientist has two solutions, which she has labeled Solution A and Solution B. Each contains salt. She knows that Solution A is
vampirchik [111]

we know that A has 60% of salt, so if way we had "x" amount of ounces of A solution the amount in it will be 60% of "x", or namely (60/100)*x = 0.6x.

Likewise for solution B if we had "y" ounces of it, the amount of salt in it will be (75/100) * y or 0.75y, thus

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{oz of }}{amount}\\ \cline{2-4}&\\ A&x&0.60&0.6x\\ B&y&0.75&0.75y\\ \cline{2-4}&\\ mixture&60&0.65&39 \end{array}~\hfill \begin{cases} x+y=60\\ 0.6x+0.75y=39 \end{cases} \\\\\\ \stackrel{\textit{since we know that}}{x+y=60}\implies y = 60 - x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.6x+0.75(60-x)=39}

0.6x+45-0.75x=39\implies -0.15x+45=39\implies -0.15x=-6 \\\\\\ x = \cfrac{-6}{-0.15}\implies \boxed{x = 40} \\\\\\ \stackrel{\textit{we know that}}{y = 60 - x}\implies y = 60-40\implies \boxed{y = 20}

3 0
2 years ago
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