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3 years ago

Find AB if ZB=3x-17 and ZA=x+5

Mathematics

1 answer:

Aloiza [94]3 years ago

6 0

Answer:

AB = 4x-12

Step-by-step explanation:

AB = ZA+ZB

= x+5 + 3x-17

= 4x-12

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3 years ago

Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.

maksim [4K]

Answer:

$\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]$

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

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Therefore the sum of the first n terms is:

$\Sigma_{k=1}^{n}(ar^{k-1})$

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

$\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]$

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3 years ago

Is this equation linear or nonlinear y=4x(8-x)

sweet-ann [11.9K]

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3 years ago

Read 2 more answers

PLS ANSWER QUICK! Thanks!

ziro4ka [17]

Answer:

The correct answer would be $a=\sqrt{c^2-b^2}$

Step-by-step explanation:

given $a^2+b^2=c^2$ we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract $b^2$ from each side

$a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2$

now we have $a^2=c^2-b^2$

step 2 take the square root of each side

$\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}$

we're left with $a=\sqrt{c^2-b^2}$

Hence your answer is A

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3 years ago

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Bas_tet [7]

Answer:

$47

Step-by-step explanation:

If she spent 47, and had none after, she spent 47.

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3 years ago