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Sergeu [11.5K]
3 years ago
12

When simplifying the following problem what calculation should be done first:

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0
(
−
2
)
(
6
)
+
3
(
5
−
4
+
2
)
=
−
12
+
3
(
5
−
4
+
2
)
=
−
12
+
3
(
1
+
2
)
=
−
12
+
(
3
)
(
3
)
=
−
12
+
9
=
−
3
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Events A and B satisfy the conditions shown P (A)=0.3 P (B)=0.1 P (A and B)=0.03 What statement about the two events must be tru
Sliva [168]

Answer:

D

Step-by-step explanation:

P(A)=0.3

P(B)=0.1

P(A)×P(B)=0.3×0.1=0.03

P(A and B)=P(A)×P(B)

They are independent.

6 0
3 years ago
Graph the line whose y-intercept is - 9 and whose x-intercept is 5.
Nostrana [21]

Answer:

y=1.8x-9

Step-by-step explanation:

if they are intercepts so the x/y will be zero, so in y intetceot the x is zero, and in the x itercept the y is zero.

0,-9

5,0

we calculate the slooe / rise

-9-0/0-5 = 1.8

we then use this formula

y-y1=rise(x-x1)

y-0=1.8(x-5)

y=1.8x-9

4 0
3 years ago
Can anyone find the answer for this equation?
Lynna [10]
66 hope it is right
5 0
3 years ago
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

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3 years ago
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Answer:

I think the answer is C. heating a cup of tea or D. Drying clothes in Dryer

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