Answer:
x ≤ 3
Step-by-step explanation:
Given
2(4 + 2x) ≥ 5x + 5 ← distribute parenthesis on left side
8 + 4x ≥ 5x + 5 ( subtract 4x from both sides )
8 ≥ x + 5 ( subtract 5 from both sides )
3 ≥ x , then
x ≤ 3
Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
To learn more about Range, Domain and functions refer to:
brainly.com/question/1942755
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Answer:
S = 2
Step-by-step explanation:
1st step: Simplify both sides of the equation
4/5 s - 3/4 s = 1/10
4/5 s + -3/4 s = 1/10
(4/5 s + -3/4 s) = 1/10 (combine like terms)
1/20 s = 1/10
1/20 s = 1/10
step 2: multiply both sides by 20
20 * (1/20 s) = 20 * (1/10)
s = 2
Hope this helped!
